Answered by : david-cao
>>> L = ['abc', 'ABD', 'aBe']
>>> sorted(L, key=str.lower, reverse=True) # Sorting built-in
['aBe', 'ABD', 'abc']
>>> L = ['abc', 'ABD', 'aBe']
>>> sorted([x.lower() for x in L], reverse=True)
['abe', 'abd', 'abc']Source : https://www.howtouselinux.com/post/sort-list-in-python | Last Update : Mon, 28 Feb 22
Answered by : sparkling-salmon-n0rria8192us
prime_numbers = [11, 3, 7, 5, 2]
# sort the list
prime_numbers.sort()
print(prime_numbers)
# Output: [2, 3, 5, 7, 11]Source : https://www.programiz.com/python-programming/methods/list/sort | Last Update : Wed, 02 Mar 22
Answered by : bhudis-wittayanusit
prime_numbers = [11, 3, 7, 5, 2]
# sorting the list in ascending order
prime_numbers.sort()
print(prime_numbers)
# Output: [2, 3, 5, 7, 11]Source : https://www.programiz.com/python-programming/methods/list/sort | Last Update : Tue, 14 Jun 22
Answered by : natural-morons
l = [64, 25, 12, 22, 11, 1,2,44,3,122, 23, 34]
for i in range(len(l)): for j in range(i + 1, len(l)): if l[i] > l[j]: l[i], l[j] = l[j], l[i]
print lSource : https://stackoverflow.com/questions/11964450/python-order-a-list-of-numbers-without-built-in-sort-min-max-function | Last Update : Tue, 10 May 22
Answered by : happy-herring-hukhsrjbq03l
>>> sorted([5, 2, 3, 1, 4])
[1, 2, 3, 4, 5]Source : https://docs.python.org/3/howto/sorting.html | Last Update : Wed, 17 Nov 21
Answered by : natural-morons
data_list = [-5, -23, 5, 0, 23, -6, 23, 67]
new_list = []
while data_list: minimum = data_list[0] # arbitrary number in list for x in data_list: if x < minimum: minimum = x new_list.append(minimum) data_list.remove(minimum)
print new_listSource : https://stackoverflow.com/questions/11964450/python-order-a-list-of-numbers-without-built-in-sort-min-max-function | Last Update : Tue, 10 May 22
Answered by : aby-mathew
# Sort with an inner object
# Here it will sort with "book_no"
# [
# {
# "key": "book-key-1",
# "book_no": 1,
# "name": "My Book Name 1"
# },
# {
# "key": "book-key-2",
# "book_no": 2,
# "name": "My Book Name 2"
# }
# ]
def sortOnNumber(e): return e['book_no']
@app.get('/getBooks')
def getBooks(): res = next(booksDb.fetch()) res.sort(key=sortOnNumber) if res: return res raise HTTPException(404,"Not found")Source : | Last Update : Wed, 22 Jun 22