Answered by : boris-krischel
# sort() will change the original list into a sorted list
vowels = ['e', 'a', 'u', 'o', 'i']
vowels.sort()
# Output:
# ['a', 'e', 'i', 'o', 'u']
# sorted() will sort the list and return it while keeping the original
sortedVowels = sorted(vowels)
# Output:
# ['a', 'e', 'i', 'o', 'u']Source : https://www.programiz.com/ | Last Update : Tue, 25 Feb 20
Answered by : lively-lyrebird-u15ujwlpnxuj
vowels = ['e', 'a', 'u', 'o', 'i']
vowels.sort()Source : | Last Update : Fri, 22 May 20
Answered by : simthegreat
l=[1,3,2,5]
l= sorted(l)
print(l)
#output=[1, 2, 3, 5]
#or reverse the order:
l=[1,3,2,5]
l= sorted(l,reverse=True)
print(l)
#output=[5, 3, 2, 1]Source : | Last Update : Sat, 11 Jul 20
Answered by : zachary-hankin
a_list = [3,2,1]
a_list.sort()Source : | Last Update : Sat, 26 Sep 20
Answered by : alex-wojtowicz
# example list, product name and prices
price_data = [['product 1', 320.0], ['product 2', 4387.0], ['product 3', 2491.0]]
# sort by price
print(sorted(price_data, key=lambda price: price[1]))Source : | Last Update : Wed, 27 Oct 21
Answered by : impossible-ibex-ti1p6o6jo8tl
>>> a = [5, 2, 3, 1, 4]
>>> a.sort()
>>> a
[1, 2, 3, 4, 5]Source : https://docs.python.org/3/howto/sorting.html | Last Update : Mon, 16 Aug 21
Answered by : natural-morons
l = [64, 25, 12, 22, 11, 1,2,44,3,122, 23, 34]
for i in range(len(l)): for j in range(i + 1, len(l)): if l[i] > l[j]: l[i], l[j] = l[j], l[i]
print lSource : https://stackoverflow.com/questions/11964450/python-order-a-list-of-numbers-without-built-in-sort-min-max-function | Last Update : Tue, 10 May 22
Answered by : super-swan-5av0uymvhmww
old_list = [3,2,1]
old_list.sort()Source : | Last Update : Mon, 29 Jun 20
Answered by : bhudis-wittayanusit
prime_numbers = [11, 3, 7, 5, 2]
# sorting the list in ascending order
prime_numbers.sort()
print(prime_numbers)
# Output: [2, 3, 5, 7, 11]Source : https://www.programiz.com/python-programming/methods/list/sort | Last Update : Tue, 14 Jun 22
Answered by : odunosho-moses
"""Sort in ascending and descending order"""
list_test = [2, 1, 5, 3, 4]
#ascending is by default for sort
#Time Complexity: O(nlogn)
list_test.sort()
#For descending order
#Time Complexity: O(nlogn)
list_test.sort(reverse=True)
#For user-define order
list_test.sort(key=..., reverse=...) Source : | Last Update : Tue, 12 Jul 22