Question : haskell function composition
Answered by : david-aypca0pmixxk
(.) :: (b -> c) -> (a -> b) -> (a -> c)
(f.g) x = f (g x)
Source : | Last Update : Fri, 25 Feb 22
Answered by : david-aypca0pmixxk
(.) :: (b -> c) -> (a -> b) -> (a -> c)
(f.g) x = f (g x)
Source : | Last Update : Fri, 25 Feb 22