Question : indexerror: invalid index to scalar variable.
Answered by : isaac-dtlde76ih65h
# You might be trying to index a scalar (non-iterable) value:
[y[1] for y in y_test]
# ^ this is the problem
# When you call [y for y in test] you are iterating over the values already, so you get a single value in y.
# Your code is the same as trying to do the following:
y_test = [1, 2, 3]
y = y_test[0] # y = 1
print(y[0]) # this line will fail
# instead you could use a for loop:
for y in y_test: results.append(..., y)
Source : | Last Update : Mon, 06 Jun 22
Question : invalid index to scalar variable
Answered by : you
# Sample code
try: variable = 42 # Example scalar variable index = 5 # Example invalid index value = variable[index] print(value) # Here, we won't reach this line as an error will be raised
except IndexError: print("Invalid index!")
Source : | Last Update : Tue, 19 Sep 23
Question : IndexError: invalid index to scalar variable.
Answered by : you
# Example code block
scalar_variable = 5 # A scalar variable
# Attempting to index the scalar variable
index = 2
try: result = scalar_variable[index] print(result)
except IndexError as e: print("Error:", e)
# Potential solution: Validate the index before accessing the element
if isinstance(scalar_variable, (list, tuple)) and 0 <= index < len(scalar_variable): result = scalar_variable[index] print(result)
else: print("Invalid index or scalar variable is not iterable")
Source : | Last Update : Mon, 18 Sep 23