Answered by : mysterious-manx-zj6ufz4d16q8

import scala.io.Source
val filename = "fileopen.scala"
for (line <- Source.fromFile(filename).getLines) { println(line)
}

Source : https://alvinalexander.com/scala/how-to-open-read-text-files-in-scala-cookbook-examples/ | Last Update : Thu, 31 Dec 20