Answered by : mitrofanos-ntatidis

import java.util.Random;
Random rand = new Random();
int random_integer = rand.nextInt(upperbound-lowerbound) + lowerbound;

Source : https://stackoverflow.com/questions/11743267/get-random-numbers-in-a-specific-range-in-java | Last Update : Thu, 28 May 20

Answered by : exuberant-eagle-qeo50utovxrx

(int)(Math.random() * ((max - min) + 1)) + min
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Source : https://mkyong.com/java/java-generate-random-integers-in-a-range/ | Last Update : Sat, 28 Mar 20

Answered by : gprata

import java.util.concurrent.ThreadLocalRandom;
// nextInt is normally exclusive of the top value,
// so add 1 to make it inclusive
int randomNum = ThreadLocalRandom.current().nextInt(min, max + 1);

Source : https://stackoverflow.com/questions/363681/how-do-i-generate-random-integers-within-a-specific-range-in-java | Last Update : Mon, 02 Nov 20

Answered by : brad-m5nqipa1purf

public int getRandomNumber(int min, int max) { return (int) ((Math.random() * (max - min)) + min);
}

Source : | Last Update : Mon, 19 Jul 21

Answered by : impossible-impala-gp45r1f4ycvw

int rand = ThreadLocalRandom.current().nextInt(x,y);

Source : | Last Update : Tue, 19 May 20