Answered by : breakable-barracuda-0jncfurmq0n9

long l = 12345L;
String str = Long.toString(l);
System.out.println(str); //prints '12345'

Source : https://www.journaldev.com/18333/java-long-to-string#longtostring | Last Update : Mon, 15 Jun 20

Answered by : breakable-barracuda-0jncfurmq0n9

long l = 12345L;
String str = new StringBuilder().append(l).toString();

Source : https://www.journaldev.com/18333/java-long-to-string#longtostring | Last Update : Mon, 15 Jun 20

Answered by : breakable-barracuda-0jncfurmq0n9

long l = 0x11L;
String str = Long.toString(l);
System.out.println(str); //prints '17'
l = 011L;
str = Long.toString(l);
System.out.println(str); //prints '9'

Source : https://www.journaldev.com/18333/java-long-to-string#longtostring | Last Update : Mon, 15 Jun 20

Answered by : breakable-barracuda-0jncfurmq0n9

long l = 12345L;
//deprecated from Java 9, use valueOf for better performance
String str = new Long(l).toString(); // str is '12345'

Source : https://www.journaldev.com/18333/java-long-to-string#longtostring | Last Update : Mon, 15 Jun 20

Answered by : breakable-barracuda-0jncfurmq0n9

long l = 369L;
String s = String.format("%d", l);

Source : https://www.journaldev.com/18333/java-long-to-string#longtostring | Last Update : Mon, 15 Jun 20

Answered by : breakable-barracuda-0jncfurmq0n9

long l = 12345L;
String str = String.valueOf(l); // str is '12345'

Source : https://www.journaldev.com/18333/java-long-to-string#longtostring | Last Update : Mon, 15 Jun 20

Answered by : breakable-barracuda-0jncfurmq0n9

long number = 45;
System.out.println(Long.toBinaryString(number)); //101101
System.out.println(Long.toOctalString(number)); //55
System.out.println(Long.toHexString(number)); //2d
System.out.println(Long.toString(number, 5)); //140

Source : https://www.journaldev.com/18333/java-long-to-string#longtostring | Last Update : Mon, 15 Jun 20

Answered by : breakable-barracuda-0jncfurmq0n9

long l = 12345L;
String str = DecimalFormat.getNumberInstance().format(l);
System.out.println(str); //str is '12,345'
//if you don't want formatting
str = new DecimalFormat("#").format(l);
System.out.println(str); //str is '12345'

Source : https://www.journaldev.com/18333/java-long-to-string#longtostring | Last Update : Mon, 15 Jun 20