Answered by : -4gh3xspu7rl9

from datetime import datetime, timedelta
d = datetime.today() - timedelta(days=days_to_subtract)

Source : https://stackoverflow.com/questions/441147/how-to-subtract-a-day-from-a-date | Last Update : Thu, 23 Dec 21

Answered by : joe-apiwit

date_N_days_ago = datetime.now() - timedelta(days=N)

Source : | Last Update : Wed, 06 May 20

Answered by : important-ibis-8954b5iqc7mj

from datetime import datetime, timedelta
print datetime.now() + timedelta(days=5, hours=-5)

Source : https://stackoverflow.com/questions/441147/how-to-subtract-a-day-from-a-date | Last Update : Mon, 18 May 20

Answered by : fantastic-fly-xng6s6mr73zv

from datetime import datetime
birthday = datetime(1988, 2, 19, 12, 0, 0)
diff = datetime.now() - birthday
print diff
# 8954 days, 7:03:45.765329

Source : https://stackoverflow.com/questions/12126318/subtracting-dates-with-python | Last Update : Mon, 13 Dec 21