Next Day In Python Without Using Datetime

[Solved] Next Day In Python Without Using Datetime | Python - Code Explorer | yomemimo.com
Question : the day before today python datetime

Answered by : -4gh3xspu7rl9

from datetime import datetime, timedelta
d = datetime.today() - timedelta(days=days_to_subtract)

Source : https://stackoverflow.com/questions/441147/how-to-subtract-a-day-from-a-date | Last Update : Tue, 07 Dec 21

Question : next day in python without using datetime

Answered by : amna-rafique

import datetime
from datetime import timedelta
d = int(input('enter the day: '))
m = int(input('enter the month: '))
y = int(input('enter the year: '))
today = datetime.date(y, m, d)
tom = today + timedelta(days=1)
print('next day is', tom) 

Source : | Last Update : Wed, 15 Jun 22

Question : python set day of date to 1

Answered by : jessica-koekemoer

from datetime import datetime
your_date = datetime.strptime('26 June 2021', '%d %b %Y')
# Using the .replace() method:
newdatetime = your_date.replace(day=1)
# 2021-06-01 00:00:00

Source : https://stackoverflow.com/questions/12468823/python-datetime-setting-fixed-hour-and-minute-after-using-strptime-to-get-day/12468869 | Last Update : Fri, 23 Jul 21

Question : next day in python

Answered by : amna-rafique

date = int(input('enter the date: '))
month = int(input('enter the month: '))
year = int(input('enter the year: '))
x = (1, 3, 5, 7, 10)
y = (4, 6, 8, 9, 11)
if month in x and date == 31: month = month + 1 date = 1
elif month in x and date < 31: date = date + 1
elif month in y and date == 30: month = month + 1 date = 1
elif month in y and date < 31: date = date + 1
elif month == 2 and date == 28 or date == 29: month = month+1 date = 1
elif month == 2 and date < 29: date = date+1
elif month == 12 and date < 31: date = date + 1
elif month == 12 and date == 31: month = 1 date = 1 year = year + 1
print('%02d-' % date, '%02d-' % month, '%02d' % year)

Source : | Last Update : Wed, 15 Jun 22

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