## checking any elment of list_B in list_A
list_A = [1, 2, 3, 4]
list_B = [2, 3, 6]
check = any(item in list_A for item in list_B)
print(check)
# True

## checking all elements of list_B in list_A
list_A = [1, 2, 3, 4]
list_B = [2, 3]
check = all(item in list_A for item in list_B)
print(check)
# True

>>> items = set([-1, 0, 1, 2])
>>> set([1, 2]).issubset(items)
True
>>> set([1, 3]).issubset(items)
False

## using set
list_A = [1, 2, 3, 4]
list_B = [2, 3]
set_A = set(list_A)
set_B = set(list_B)
print(set_A.intersection(set_B))
# True if there is any element same
# False if there is no element same

''' check if list1 contains any elements of list2
'''
result = any(elem in list1 for elem in list2)
if result: print("Yes, list1 contains any elements of list2")
else : print("No, list1 contains any elements of list2")

##Taking examples of two python lists.
##Take examples of two lists.
list1 = [2,4,0,7,6]
list2 = [1,0,9,7,6]
##the statement for condition is.
check = any(element in list2 for element in list1)

fruits1 = ['Mango','orange','apple','jackfruit']
fruits2 = ['Mango','orange','apple','jackfruit']
new_list= all(item in fruits1 for item in fruits2)
if new_list is True: print("True")
else : print("False")

## using set
list_A = [1, 2, 3, 4]
list_B = [5,1]
set_A = set(list_A)
set_B = set(list_B)
output = False if (set_A.intersection(set_B) == set()) else True
print(output)
# True if there is any element same
# False if there is no element same

// You could use a nested Any() for this check which is available on any Enumerable:
bool hasMatch = myStrings.Any(x => parameters.Any(y => y.source == x));
// Faster performing on larger collections would be to project parameters to source and
// then use Intersect which internally uses a HashSet<T> so instead of O(n^2) for the
// first approach (the equivalent of two nested loops) you can do the check in O(n) :
bool hasMatch = parameters.Select(x => x.source) .Intersect(myStrings) .Any();
// source: https://stackoverflow.com/a/11092955

boolean var = lis1.stream().anyMatch(element -> list2.contains(element));