Answered by : happy-sloth
>>> letters = [a,b,c,d,e]
>>> 'a' in letters:
True
Source : | Last Update : Sun, 03 Jan 21
Answered by : jakub-kt3
l1 = [1]
l2 = [2,3,4]
if len(set(l1).intersection(set(l2)))==0: print('1 is not in the list (l2)')
else: # len()>0 print('1 is in the list (l2)')
Source : | Last Update : Wed, 27 Jul 22
Answered by : harit-rai
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fruits = ["apple", "banana", "cherry","banana"]
item = "apple"
if item in fruits: print("Yes, '",item,"' is in the fruits list")
Source : | Last Update : Thu, 30 Dec 21
Answered by : thoughtful-tapir-ajuw1huomuqu
if ourlist.count('to') > 0: print('"to" exists in ourlist');
Source : https://www.parthpatel.net/python-if-list-contains-value/ | Last Update : Wed, 05 Jan 22
Answered by :
if item in list: #do stuff
Source : | Last Update : Thu, 01 Jul 21
Answered by : blueeyed-bee-6mefh3de5zru
''' check if element NOT exist in list using 'in'
'''
if 'time' not in listOfStrings : print("Yes, 'time' NOT found in List : " , listOfStrings)
Source : https://thispointer.com/python-how-to-check-if-an-item-exists-in-list-search-by-value-or-condition/#:~:text=Check%20if%20element%20exist%20in%20list%20using%20list.&text=count(element)%20function%20returns%20the,given%20element%20exists%20in%20list. | Last Update : Tue, 09 Feb 21
Answered by : eric-tam
list = ["a", "a", "a", "b", "c", "d"]
if 'a' in list: print("a is in the list")
Source : | Last Update : Wed, 27 Jul 22
Answered by : promikesundays
element_you_want_to_find in list_in_you_want_to_search
Note: Don't forget to substitute both of that variables with the variables you want Conclusion: Use the in operator
Source : | Last Update : Sat, 26 Dec 20