Rails Array Pop First N Elements

[Solved] Rails Array Pop First N Elements | Haskell - Code Explorer | yomemimo.com
Question : ruby pop array

Answered by : christopher-olson

a = [1, 2, 3, 4]
a.pop()
# => 4

Source : | Last Update : Wed, 24 Jun 20

Question : rails array pop first n elements

Answered by : lior

array = [1, 2, 3, 4, 5, 6]
array.drop(2)
# => [3, 4, 5, 6]

Source : | Last Update : Fri, 26 Mar 21

Question : Ruby exclude from slice

Answered by : mysterious-manatee-ko06m5e45kjt

# First of all you have to use splat (*) operator.
# Then instead of using .slice() and .except() together, you can do this is more efficient way.
columns_to_show = ['age', 'gender', 'cast', 'fee_status']
columns_to_show = columns_to_show - hidden_columns if hidden_columns
patient.slice(*columns_to_show).values
patient.slice('age', 'gender', 'cast', 'fee_status').except(*hidden_columns) => {"cast"=>"black", "fee_status"=>"paid"}

Source : https://stackoverflow.com/questions/53007950/rails-except-array-elements-from-slice | Last Update : Fri, 14 Aug 20

Answers related to rails array pop first n elements

Code Explorer Popular Question For Haskell