Answered by : mysterious-millipede-j2wbgm1cslih
>>> l = [1, 2, 3, 4, 5]
>>> l
[1, 2, 3, 4, 5]
>>> l.pop(0)
1
>>> l
[2, 3, 4, 5]
Source : https://www.techiedelight.com/remove-first-item-from-list-python/ | Last Update : Sat, 07 Mar 20
Answered by : itchy-impala-xqthyfykiqkk
sample_list = [1, 2, 3, 4, 5]
sample_list.remove(sample_list[0])
print(sample_list)
Source : https://favtutor.com/blogs/remove-first-element-from-list-python | Last Update : Mon, 22 Nov 21
Answered by : logesh-n
list = [1,2,3]
print(list[1:3]) # output is [2,3]
Source : | Last Update : Sat, 20 Nov 21
Answered by : theo-soderstrom
del a_list[0]
Source : https://www.adamsmith.haus/python/answers/how-to-remove-the-first-element-from-a-list-in-python | Last Update : Wed, 27 Apr 22
Answered by : you
my_list = [1, 2, 3, 4, 5]
my_list.pop(0)
print(my_list)
Source : | Last Update : Tue, 19 Sep 23
Answered by : vedant-m
# Python3 code to demonstrate
# removing front element
# using pop(0)
# initializing list
test_list = [1, 4, 3, 6, 7]
# Printing original list
print ("Original list is : " + str(test_list))
# using pop(0) to
# perform removal
test_list.pop(0)
# Printing modified list
print ("Modified list is : " + str(test_list))
Source : https://www.geeksforgeeks.org/python-removing-first-element-of-list/ | Last Update : Tue, 22 Feb 22
Answered by : you
my_list = [1, 2, 3, 4, 5]
# Removing the first element using the pop() method
first_element = my_list.pop(0)
print(first_element) # Output: 1
print(my_list) # Output: [2, 3, 4, 5]
Source : | Last Update : Tue, 19 Sep 23