Answered by : poor-platypus-hv2inx5kdgvw
var age=20;
if (age < 18) { console.log("underage");
} else { console.log("let em in!");
}
Source : | Last Update : Wed, 31 Mar 21
Answered by : mohamed-essam-salem
int age = 30;
if(age >= 30 && age <= 80){ System.out.println("Old");
}else if(age < 30 && >= 1){ System.out.println("Young");
}else{ System.out.println("Not Supported");
}
Source : | Last Update : Mon, 25 Apr 22
Answered by : embarrassed-emu-podevshvt22t
if ((age >= 14) && (age < 19)) { // logical condition
status = "Eligible."; // executed if condition is true
} else { // else block is optional
status = "Not eligible."; // executed if condition is false
}
Source : https://htmlcheatsheet.com/js/ | Last Update : Wed, 14 Apr 21
Answered by : madhav
if (condition is) { true, do this
} else { false, do this
}
Source : | Last Update : Tue, 23 Aug 22
Answered by : eric-tam
int x = 30;
int y = 40;
if(y>x)
{
System.out.print("x is greater than y");
}
else
{
System.out.print("x is not greater than y");
}
Source : | Last Update : Wed, 29 Jun 22
Answered by : poor-peacock-nfojm5w3tbay
>> number=23
>> guess = input('Enter a number : ')
>> if guess == number:
>> print('Congratulations! You guessed it.')
>> elif guess < number: **( It is giving me 'Invalid Syntax')**
>> else: **( It is also giving me 'Invalid syntax')**
Source : https://stackoverflow.com/questions/7025443/else-elif-statements-not-working-in-python | Last Update : Mon, 23 May 22
Answered by : dark-dunlin-l99bs8d49qwa
To learn about Java if else statement visit website:
https://www.allaboutjava.com/2021/07/java-if-else-statements.html
Source : | Last Update : Fri, 30 Jul 21
Answered by : qd-zero
driver = webdriver.Firefox()
Source : https://stackoverflow.com/questions/54575853/how-to-set-window-position-of-firefox-browser-through-selenium-using-firefoxprof?fbclid=IwAR0S6D403SjWNFwVDj1Wq0tYSV5tqMdqrEOJmfZz-08kTA-LMU_aIqBbl_s | Last Update : Wed, 24 Aug 22
Answered by : muhammad-bilal-zzw5u8uxlmq0
var age = prompt("enter your age")
if (age>= 60){ console.log("you are older")
}
else if (age >=18){ console.log("you are adult")
}
else if (age < 18){ console.log("you are child")
}
Source : | Last Update : Sun, 28 Aug 22
Answered by : grieving-goose-iqel0u06bc77
using System;
class NumbersNotDivisibleBy3And7
{
static void Main()
{
Console.WriteLine("Enter an integer:");
int n = int.Parse(Console.ReadLine());
for (int i = 1; i <= n; i++)
{
if (i % 3 != 0 && i % 7 != 0)
{
Console.Write("{0} ", i);
}
}
Console.WriteLine();
}
}
Source : https://forum.tutorials7.com/1235/finding-numbers-not-divisible-by-3-and-7-in-c%23 | Last Update : Thu, 05 May 22