# Basic syntax:
sum(1 for item in your_list if item == "some_condition")
# This counts the items in your_list for which item == "some_condition"
#	is true. Of course, this can be changed to any conditional statement

word_counter = {}
book_title = ['great', 'expectations','the', 'adventures', 'of', 'sherlock','holmes','the','great','gasby','hamlet','adventures','of','huckleberry','fin']
for word in book_title: if word not in word_counter: word_counter[word] = 1 else: word_counter[word] += 1
print(word_counter)
# output - {'great': 2, 'expectations': 1, 'the': 2, 'adventures': 2, 'of': 2, 'sherlock': 1, 'holmes': 1, 'gasby': 1, 'hamlet': 1, 'huckleberry': 1, 'fin': 1}

mylist = ["abc", "def", "ghi", "jkl", "mno", "pqr"]
print(len(mylist))
# output 6

"""Find all occurrences of element in list"""
# If you simply want find how many times an element appears
# use the built-in function count()
def find_occur(lst, item):	return lst.count(item)
# Test -----------------------------------------------------------
print(find_occur([None, None, 1, 2, 3, 4, 5], None)) # 2
# If you wanna find where they occur instead
# - This returns the indices where element is found within a list
def find(lst, item): return [i for (i, x) in enumerate(lst) if x == item]
# Test Code ------------------------------------------------------
from random import randint, choice
lst = [randint(0, 99) for x in range(10)] # random lst
item = choice(lst) # item to find
found = find(lst, item) # lst of where item is found at
print(f"lst: {lst}", f"item: {item}", f"found: {found}", sep = "\n")