OPERASI HITUNG CAMPURAN BILANGAN CACAH,PECAHAN,dan DESIMALMapel - MTKKelas - 6

Berikut ini adalah pertanyaan dari yovyanur39 pada mata pelajaran Matematika untuk jenjang Sekolah Dasar

OPERASI HITUNG CAMPURAN BILANGAN CACAH,PECAHAN,dan DESIMALMapel - MTK

Kelas - 6 SD

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Jawaban dan Penjelasan

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Nomor 1.

$50 + 2.25 \times \frac{5}{20} \\ \\ = \frac{50}{1} + (\frac{225}{100} \times \frac{5}{20} ) \\ \\ = \frac{50}{1} + (\frac{9}{4} \times \frac{1}{4} ) \\ \\ = \frac{50}{1} + \frac{9}{16} = \frac{800 + 9}{16} \\ \\ = \frac{809}{16} = 50 \frac{9}{16}$

Nomor 2.

$60 + (4.75 \times \frac{4}{25} ) \\ \\ = \frac{60}{1} + ( \frac{475}{100} \times \frac{4}{25} ) \\ \\ = \frac{60}{1} + (\frac{19}{4} \times \frac{4}{25} ) \\ \\ = \frac{60}{1} + ( \frac{19}{1} \times \frac{1}{25} ) \\ \\ = \frac{60}{1} + \frac{19}{25} = \frac{1.500 + 19}{25} \\ \\ = \frac{1.519}{25} = 60 \frac{19}{25}$

Nomor 3.

$(2 \frac{4}{10} \times 5 \div 4 \frac{6}{8} )- 3.35 \\ \\ =( 2 \frac{2}{5} \times 5 \div 4 \frac{3}{4}) - \frac{335}{100} \\ \\ = (\frac{12}{5} \times \frac{5}{1} \times \frac{4}{19}) - \frac{67}{20} \\ \\ = ( \frac{12}{1} \times \frac{1}{1} \times \frac{4}{19} ) - \frac{67}{20} \\ \\ = \frac{48}{19} - \frac{67}{20} = \frac{960 - 1.273}{380} \\ \\ = - \frac{313}{380}$

Nomor 4.

$(20 \times 2.5 )+ 5 \frac{6}{7} \\ \\ = ( \frac{20}{1} \times \frac{25}{10} ) + \frac{41}{7} \\ \\ = ( \frac{20}{1} \times \frac{5}{2} ) + \frac{41}{7} \\ \\ = ( \frac{10}{1} \times \frac{5}{1} ) + \frac{41}{7} \\ \\ = \frac{50}{1} + \frac{41}{7} = \frac{350 + 41}{7} \\ \\ = \frac{391}{7} = 55 \frac{6}{7}$

Nomor 5.

$(3 \frac{5}{10} \times 4 \div 6 \frac{9}{10} )- 8.75 \\ \\ = (3 \frac{1}{2} \times 4 \div 6 \frac{9}{10} ) - \frac{875}{100} \\ \\ = ( \frac{7}{2} \times \frac{4}{1} \div \frac{69}{10} ) - \frac{35}{4} \\ \\ = ( \frac{7}{1} \times \frac{2}{1} \times \frac{10}{69} ) - \frac{35}{4} \\ \\ = \frac{140}{69} - \frac{35}{4} = \frac{560 - 2.415}{276} \\ \\ = - \frac{1.855}{276}$