Penjelasan:

Balok ABCD.EFGH @ 5x4x3

p = 5cm, l = 4cm, t = 3cm

cmDitanya:

Diagonal ruang= ?

iagonal ruang= ?Jawab:

iagonal ruang= ?Jawab:AC (diagonal bidang) dengan AB = 5 dan BC = 4

AC = √[(AB)² + (BC)²]

AC = √[(AB)² + (BC)²]AC = √[(5cm)² + (4cm)²]

cm)²]AC = √(25cm² + 16cm²)

cm²)AC = √41cm²

cm²AC = 20,5 cm

cmAG (diagonal ruang) dengan AC = 20,5 dan CG = 3

AG = √[(AC)² + (CG)²]

AG = √[(AC)² + (CG)²]AG = √[(20,5cm)² + (3cm)²]

cm)²]AG = √(41cm² + 9cm²)

cm²)AG = √50cm²

m²AG = 25cm

5cmSehingga panjang diagonal ruang adalah25cm.