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Jawaban

3,8/5

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nurulshufa

Terpelajar

153 jawaban

74.1 rb orang terbantu

2x²-4x-3 = 0

a= 2 ; b= -4 ; c= -3

(α+β) = -b/a = -(-4)/2 = 2

(α.β) = c/a = -3/2

akar-akar = α-3 ; β-3

Jumlah Akar = (α-3) + (β-3)

= (α+β) - 6

= 2 -6

= -4

Hasil kali Akar = (α-3)(β-3)

= α.β -3α-β +9

= (α.β) -3(α+β) +9

= -3/2 -3.2 +9

= -3/2 -6 +9

= -3/2 + 3

= -3/2 + 6/2

= 3/2

Persamaan Kuadrat : x² - (Jumlah Akar)x+ Hasil Kali Akar = 0

x² -(-4)x + 3/2 =0

x² +4x + 3/2 = 0 (dikali 2)

2x² +8x +3 = 0 (E)