1. Sekolah Dasar
  2. Sekolah Menengah Pertama
  3. Sekolah Menengah Atas
  4. Mata Pelajaran
  5. Programming

Question._______________________f(x) = x² + 23x² × x²f(3!) = ....______________________RULES .-.•

Berikut ini adalah pertanyaan dari CallMePutri01 pada mata pelajaran Matematika untuk jenjang Sekolah Menengah Pertama

Question._______________________

f(x) = x² + 23x² × x²
f(3!) = ....
______________________

RULES .-.
• Pakai cara ygy.
• ngasal? report -_-
• Rapi ygy.
• Lengkap = beA :v
• Good luck .-.
_______________________

v:​

Jawaban dan Penjelasan

Berikut ini adalah pilihan jawaban terbaik dari pertanyaan diatas.

SOAL 1

___________________________________________

f(x) = x² + 23x² × x²

___________________________________________

\\

f(3!) = (3!)² + 23(3!)² × (3!)²

f(3!) = (3 × 2 × 1)² + 23(3 × 2 × 1)² × (3 × 2 × 1)²

f(3!) = (6 × 1)² + 23(6 × 1)² × (6 × 1)²

f(3!) = 6² + 23(6)² × 6²

f(3!) = (6 × 6) + [23 × (6 × 6)] × (6 × 6)

f(3!) = 36 + [23 × 36] × 36

f(3!) = 36 + 828 × 36

f(3!) = 36 + 29.808

f(3!) = 29.844

\\

{\mathcal\color{purple}{{\pink{\underline{\purple{\underline\bold{\pink{K}\bold\color{violet}{h\bold{\pink{a}\bold\color{violet}{d\bold{\pink{i}\bold\color{violet}{j\bold{\pink{a}\bold\color{violet}{h\bold{\pink{A}\bold\color{violet}{m\bold{\pink{j}\bold\color{violet}{a\bold{\pink{d}\bold\color{violet}{1\bold{\pink{2}}}}}}}}}}}}}}}}}}}}}}

[tex] \huge{\tt\pink{Penyelesaian :}}[/tex]__________________• Soalan :f(x) = x² + 23x² × x²f(x) = x² + 23x² × x²f(3!) = ....-------------------------------------------• Jawabannye :f(3 × 2 × 1) = 3!² + 23(3!²) × 3!²f(3!) = 6² + 23(6²) × 6²f(3!) = (6 × 6) + 23(6 × 6) × (6 × 6)f(3!) = 36 + 23(36) × 36f(3!) = 36 + 828 × 36f(3!) = 36 + 29.808f(3!) = 29.844___________________#Semoga_Membantu#Maaf_kalo_Salah~CMIIW[tex]\colorbox{black}{\pink{\boxed{✿✧ \: \colorbox{black}{ \purple{\boxed{\tt{ \: \blue{❛❜ \: Rixxel} \: \red{x} \: \pink{Reina \: ❛❜} \: }}}} \: ✧✿}}}[/tex][tex] \huge{\tt\pink{Penyelesaian :}}[/tex]__________________• Soalan :f(x) = x² + 23x² × x²f(x) = x² + 23x² × x²f(3!) = ....-------------------------------------------• Jawabannye :f(3 × 2 × 1) = 3!² + 23(3!²) × 3!²f(3!) = 6² + 23(6²) × 6²f(3!) = (6 × 6) + 23(6 × 6) × (6 × 6)f(3!) = 36 + 23(36) × 36f(3!) = 36 + 828 × 36f(3!) = 36 + 29.808f(3!) = 29.844___________________#Semoga_Membantu#Maaf_kalo_Salah~CMIIW[tex]\colorbox{black}{\pink{\boxed{✿✧ \: \colorbox{black}{ \purple{\boxed{\tt{ \: \blue{❛❜ \: Rixxel} \: \red{x} \: \pink{Reina \: ❛❜} \: }}}} \: ✧✿}}}[/tex][tex] \huge{\tt\pink{Penyelesaian :}}[/tex]__________________• Soalan :f(x) = x² + 23x² × x²f(x) = x² + 23x² × x²f(3!) = ....-------------------------------------------• Jawabannye :f(3 × 2 × 1) = 3!² + 23(3!²) × 3!²f(3!) = 6² + 23(6²) × 6²f(3!) = (6 × 6) + 23(6 × 6) × (6 × 6)f(3!) = 36 + 23(36) × 36f(3!) = 36 + 828 × 36f(3!) = 36 + 29.808f(3!) = 29.844___________________#Semoga_Membantu#Maaf_kalo_Salah~CMIIW[tex]\colorbox{black}{\pink{\boxed{✿✧ \: \colorbox{black}{ \purple{\boxed{\tt{ \: \blue{❛❜ \: Rixxel} \: \red{x} \: \pink{Reina \: ❛❜} \: }}}} \: ✧✿}}}[/tex]

Semoga dengan pertanyaan yang sudah terjawab oleh Kireina746 dapat membantu memudahkan mengerjakan soal, tugas dan PR sekolah kalian.

Apabila terdapat kesalahan dalam mengerjakan soal, silahkan koreksi jawaban dengan mengirimkan email ke yomemimo.com melalui halaman Contact

Last Update: Sun, 07 Aug 22
<< Previous Post
Next Post >>