Qzz12³ - (9 × 9) = ....4³ = ....Question by : Menamvar Elpiji Lemot Viva air Iron men Alpukat Nanas Apel:)

Question

Qzz12³ - (9 × 9) = ....4³ = ....Question by : Menamvar Elpiji Lemot Viva air Iron men Alpukat Nanas Apel:)​

staralya78 · Accepted Answer

ꕥ PendahuluanPerpangkatan adalah Perkalian. Secara berulang》Bentuk umum《a^n = a × a × a ... × a × a( a dikalikan sebanyak n )a = basisn = Eksponen atau pangkatContoh= 2⁴= ( 2 × 2 ) × ( 2 × 2 )= ( 2 + 2 ) × ( 2 + 2 )= 4 × 4= ( 4 + 4 ) + ( 4 + 4 )= 8 + 8= 16--( ￣ ▽￣)∠ ))= 2³= 2 × 2 × 2= (2+2) × 2= 4 × 2= (4+4)= 8ꕥ Pembahasan(¡)= 12³ - (9×9)= (12.12.12) - 81= (144.12) - 81= 1.728 - 81= [tex]	t{1.647}[/tex](¡¡)= 4³ = (4.4.4)= (16.4)= [tex]	t{64}[/tex]ꕥ Pelajari lebih lanjut➠ Pengertian Bilangan berpangkathttps://brainly.co.id/tugas/44290911https://brainly.co.id/tugas/44290911➠ Contoh Soal Bilangan berpangkathttps://brainly.co.id/tugas/46743209https://brainly.co.id/tugas/46743209ꕥ Detail Jawaban❐ Kelas : 9❐ mapel : matematika❐ materi : bilangan berpangkat❐ kunci Jawaban : Operasi bilangan berpangkat❐ kode kategorisasi : 9.2.7

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