A family needs at least 900 units of protein and

Berikut ini adalah pertanyaan dari nyxii pada mata pelajaran Matematika untuk jenjang Sekolah Menengah Pertama

A family needs at least 900 units of protein and 400 units of lipids in food per day. Each kilogram of beef contains 800 units of protein and 200 units of lipids. Each kilogram of pork contains 600 units of protein and 400 units of lipids. Knowing that this family can only buy a maximum of 1.5 kilograms of beef and 1 kilogram of pork per day, the price of 1 kilogram of beef is $10, and 1 kilogram of pork is $5. How many kilograms of meat they should get for the least price but still meet the requirements at the start of the problem?​

Jawaban dan Penjelasan

Berikut ini adalah pilihan jawaban terbaik dari pertanyaan diatas.

Materi : SPLDV

Pemisalan :

Unit Protein = ( x )

Unit Lipids = ( y )

kg Beef = ( a )

kg Pork = ( b )

Satuan Dollar

$1 = 1

\_____________/

1 = 900x + 400y

10 = a = 800x + 200y

5 = b = 600x + 400y

---

800x¹ + 600x² = 900x [ 8x¹ + 6x² = 9x ]

200y¹ + 400y² = 400y [ y¹ + 2y² = 2y ]

---

a = 2b [ harga ]

---

1,5a + b = 1 [ Max ]

SPLDV

8x¹ + 6x² = 9x [ x¹ = ( p ) dan x² = ( q ) ]

y¹ + 2y² = 2y [ y¹ = ( p ) dan y² = ( q ) ]

Satuan 9x = ( 9 ) dan 2y = 2

______________________________

8p + 6q = 9

p + 2q = 2 [ p = 2 - 2q ]

______________________________

8( 2 - 2q ) + 6q = 9

16 - 16q + 6q = 9

16q - 6q = 16 - 9

10q = 7

[ q = 7/10 ]

---

p = 2 - 2q

p = 2/1 - 2( 7/10 )

p = 10/5 - 7/5

[ p = 3/5 ]

Hasil / Result :

{ p = 3/5 = 60% dan q = 7/10 = 70% }

Perbandingan p : q = 6 : 7

Nilai Protein

60% × Beef = 480x

70% × Lipids = 420x

Nilai Lipids

60% × Beef = 120y

70% × Lipids = 280y

Kesimpulan

60% Beef = 1,5 × 60% = 3/2 × ⅗ = 9/10 = 0,9 kg

70% Lipids = 1 × 70% = 1/1 × 7/10 = 7/10 = 0,7 kg

Biaya = 0,9($10) + 0,7($5) = $9 + $3,5 = $12,5

Semoga bisa membantu

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Last Update: Fri, 17 Feb 23