[tex] \ \ [/tex]B = (5!!)²A = f(1) = 1x - 1xL = 2(2²)O = 1⁰ × 2⁰N = 6----------B + A + L + O + N ------------[tex] \ \ [/tex]kyaaa v: ( ea )

Question

[tex] \ \ [/tex]B = (5!!)²A = f(1) = 1x - 1xL = 2(2²)O = 1⁰ × 2⁰N = 6----------B + A + L + O + N ------------[tex] \ \ [/tex]kyaaa v: ( ea ) ​

Nelsyasj · Accepted Answer

Jawaban:[tex] \ [/tex]Penyelesaian soal :[tex] \ [/tex]nilai BB = (5!!)²B = (5 × 2 × 1)²B = (15 × 1)²B = 15²B = 15 × 15B = 225[tex] \ [/tex]nilai AA = f(1) = 1x - 1xA = f(1) = 1(1) - 1(1)A = f(1) = (1 × 1) - 1(1)A = f(1) = 1 - (1 × 1)A = f(1) = 1 - 1A = f(1) = 0A = 0[tex] \ [/tex]nilai LL = 2(2²)L = 2(2 + 2)L = 2(4)L = (2 × 4)L = 8[tex] \ [/tex]nilai OO = 1⁰ × 2⁰O = 1 × 1O = 2[tex] \ [/tex]Ket.a⁰ = 1 angka yg di pangkatkan 0 maka hasil nya 1.[tex] \ [/tex]Jika[tex] \ [/tex]B = (5!!)²A = f(1) = 1x - 1xL = 2(2²)O = 1⁰ × 2⁰N = 6----------maka[tex] \ [/tex][tex]	t{{{B + A + L + O + N }}}[/tex][tex]	t{{{(5!!)² + (1x - 1x) + 2(2²) + (1⁰ × 2⁰) + 6 }}}[/tex][tex]	t{{{225 + 0 + 8 + 2 + 6}}}[/tex][tex]	t{{{225 + 8 + 2 + 6 }}}[/tex][tex]	t{{{ 225 + 10 + 6}}}[/tex][tex]	t{{{235 + 6}}}[/tex][tex]	t{{{241}}}[/tex][tex] \ [/tex]Kesimpulan :[tex] \ [/tex]Jadi, hasil dari B + A + L + O + N adalah 241[tex] \ [/tex]Detail jawaban :[tex] \ [/tex]Mapel : Matematika.Kelas : VI.Materi : Operasi Hitung Bilangan Cacah.Kode Soal : 2.Kode Kategorisasi : 6.2.1[tex] \ [/tex][[SN]][tex] \ [/tex]

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[tex] \\ \\ [/tex]B = (5!!)²A = f(1) =

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