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Soal terlampir___________ Ngasal = kick​

Berikut ini adalah pertanyaan dari Ficcooo pada mata pelajaran Matematika untuk jenjang Sekolah Menengah Pertama

Soal terlampir
___________
Ngasal = kick​
Soal terlampir___________ Ngasal = kick​

Jawaban dan Penjelasan

Berikut ini adalah pilihan jawaban terbaik dari pertanyaan diatas.

Nomor 1a

{y}^{3} \times {2y}^{7} \times {(3y)}^{2} \\ = {y}^{3} \times {2y}^{7} \times {9y}^{2} \\ = (1 \times 2 \times 9) \times ( {y}^{3 + 7 + 2} ) \\ = 18 \times {y}^{12 } \\ = {18y}^{12}

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Nomor 1b

b \times {2y}^{7} \times {b}^{3} \times {y}^{2} \\ = ( {b}^{1 + 3} ) \times ( {y}^{7 + 2} ) \\ = {b}^{4} \times {y}^{9} \\ = {b}^{4} {y}^{9}

\\

Nomor 1c

{3m}^{3} \times {(mn)}^{4} \\ = {3m}^{3} \times {m}^{4} {n}^{4} \\ = 3 \times ( {m}^{3 + 4} ) \times {n}^{4} \\ = 3 \times {m}^{7} \times {n}^{4} \\ = {3m}^{7} {n}^{4}

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Nomor 1d

( { {tn}^{3}) }^{4} \times {2t}^{3} \\ = {t}^{4} {n}^{12} \times 2 {t}^{3} \\ = 2 \times {n}^{12} \times ( {t}^{4 + 3} ) \\ = 2 \times {n}^{12} \times {t}^{7}

\\

Nomor 1e

{2x}^{3} \times 3( {x}^{2} {y}^{2} ) {}^{3} \times {(5y)}^{4} \\ = {2x}^{3} \times 3( {x}^{6} {y}^{6} ) \times {625y}^{4} \\ = {2x}^{3} \times {3x}^{6} {3y}^{6} \times {625y}^{4} \\ = (2 \times 3 \times 3 \times 625) \times{x}^{6} \times {y}^{6 + 4} \\ = 11.250 \times {x}^{6} \times {y}^{10} \\ = 11.250 {x}^{6} {y}^{10}

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Nomor 2a

\frac{ {0.5}^{7} }{ {0.5}^{3} } \\ = {0.5}^{7 - 3} \\ = {0.5}^{4}

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Nomor 2b

\frac{ {5}^{7} }{ {5}^{3} \times {5}^{3} } \\ \\ = {5}^{7 - (3 + 3)} \\ \\ = {5}^{7 - 6} \\ \\ = {5}^{1} \\ \\ = 5

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Nomor 2c

\frac{ {2}^{7} \times {6}^{7} }{ {4}^{7} } \\ \\ = \frac{ {2}^{7} \times {(2 \times 3)}^{7} }{ {( {2}^{2} )}^{7} } \\ \\ = \frac{ {2}^{7} \times {2}^{7} \times {3}^{7} }{ {2}^{14} } \\ \\ = ( {2}^{7 + 7 - 14} ) \times {3}^{7} \\ \\ = {2}^{0} \times {3}^{7} \\ \\ = 1 \times {3}^{7} \\ \\ = {3}^{7}

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Nomor 2d

\frac{ {6}^{7} \times {3}^{3} }{ {2}^{7} } \\ \\ = \frac{( {2 \times 3)}^{7} \times {3}^{3} }{ {2}^{7} } \\ \\ = \frac{ {2}^{7} \times {3}^{7} \times {3}^{3} }{ {2}^{7} } \\ \\ = ( {2}^{7 - 7} ) \times ( {3}^{7 + 3} ) \\ \\ = {2}^{0} \times {3}^{10} \\ \\ = 1 \times {3}^{10} \\ \\ = {3}^{10}

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Nomor 2e

\frac {3 \times {5}^{4}}{ {5}^{3} } - 15 \\= 3 \times ({5}^{4 - 3} ) - 15 \\ = 3 \times {5}^{1} - 15 \\ = 3 \times 5 - 15 \\ = 15 - 15 \\ = 0

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Nomor 2f

12 + \frac{ {4}^{7} }{ {4}^{6} } \\ = 12 + ( {4}^{7 - 6} ) \\ = 12 + {4}^{1} \\ = 12 + 4 \\ = 16

\\

Nomor 2g

\frac{ {4}^{5} }{ {4}^{4} } - \frac{ {2}^{4} }{ {2}^{4} } \times 6 \\ \\ = ( {4}^{5 - 4} ) - ( {2}^{4 - 4} ) \times 6 \\ \\ = {4}^{1} - {2}^{0} \times 6 \\ \\ = 4 - 1 \times 6 \\ \\ = 4 - 6 \\ \\ = - 2

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Nomor 2h

\frac{ {10}^{6} \times {4}^{3} }{ {25}^{3} \times {8}^{3} } \\ \\ = \frac{( {2 \times 5)}^{6} \times { ({2}^{2} )}^{3}}{ { ({5}^{2} )}^{3} \times { ({2}^{3}) }^{3} } \\ \\ = \frac{ {2}^{6} \times {5}^{6} \times {2}^{6} }{ {5}^{6} \times {2}^{9} } \\ \\ = ( {2}^{(6 + 6) - 9} ) \times ( {5}^{6 - 6} ) \\ \\ = {2}^{12 - 9} \times {5}^{0} \\ \\ = {2}^{3} \times 1 \\ \\ = {2}^{3}

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Last Update: Sun, 16 Oct 22
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