TRansfor Geo
Dilatasi [ P(a,b), skala = k]
x' = k(x - a) + a
y' = k(y -b) + b

Diketahui bayangan hasil dilatasi dengan pusat (1,3) dan faktor skala k = -4 dari titik K dan L adalah K'(-3,7) dan L'(1,-9).

i) K(x, y)   D[ P(1, 3), k= -4] ---> k' (- 3, 7)
a= 1, b= 3 , k = - 4, x' = -3 , y' = 7

x' = k(x - a) + a
-3 =-4(x - 1) + 1
-4 = - 4(x - 1)
1 = x- 1
x=  2

y' = k(y -b) + b

7=  -4(y - 3)+  3
4 = - 4(y -3)
y - 3= - 1
y = 2

kordinar K(x,y) = (2,2)

ii) L(x,y)  D[P(1, 3), k= -4] ---> L' (1,-9)
a= 1,b =3 , k = - 4, x' = 1 ,  y' = 9

x' = k(x - a) + a
1 =  -4(x - 1) + 1
0 = -4(x - 1)
x-  1 = 0
x= 1

y' = k(y -b) + b
-9 = -4(y - 3) + 3
-12 = - 4(y -3)
y -3 = 3
y =  6

L(x, y) = (1, 6)