Jawaban:

[Gelombang Cahaya]

Penjelasan dengan langkah-langkah:

Diketahui

λ = 9.000 nm

N = 1.917.000 garis/cm

m = 1

Ditanya

α = ...

Jawaban

d = 1/N

= 1/1.917.000 garis/cm

= 0,0000005216484089723 cm

= 5,216484089723 x 10⁻⁹ m

d(sin α) = m.λ

5,216484089723 x 10⁻⁹(sin α) = 1x9.000 nm

Sin (α) = 9000 nm/5,216484089723 x 10⁻⁹m

Sin (α) = 9x10³

5,216484089723x10⁻⁹

= 1,7253x10⁻⁶

Sin (α) = 1,7253x10⁻⁶

(α) = (9,8852408x10⁻⁵)⁰

(α) = (0,000098852408)⁰

Detail Jawaban:

Mapel : Fisika

Kelas : 12 / [XII] SMA

Materi : Gelombang Cahaya

Kode Kategorisasi : -

Kata Kunci : Gelombang Cahaya

Demikian

Semoga bermanfaat dan bermanfaat!