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TOLONG BANG/KAK BESOK DI KUMPUL​

Berikut ini adalah pertanyaan dari yusufpurba0405 pada mata pelajaran Matematika untuk jenjang Sekolah Menengah Pertama

TOLONG BANG/KAK BESOK DI KUMPUL




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TOLONG BANG/KAK BESOK DI KUMPUL​

Jawaban dan Penjelasan

Berikut ini adalah pilihan jawaban terbaik dari pertanyaan diatas.

Nomor 1a

1 + 5 + 9 + 13 + ...

a = 1

b = 5 - 1 = 4

S12 = 12/2 × (2(1) + (12 - 1) 4)

S12 = 6 × (2 + 11 × 4)

S12 = 6 × (2 + 44)

S12 = 6 × 46

S12 = 276

Nomor 1b

20 + 16 + 12

a = 20

b = 16 - 20 = -4

S12 = 12/2 × (2(20) + (12 - 1) (-4))

S12 = 6 × (40 + 11 × (-4))

S12 = 6 × (40 - 44)

S12 = 6 × (-4)

S12 = -24

Nomor 2a

4 + 12 + 36

a = 4

r = 12/4 = 3

S7 = (4(3^7 - 1))/(3 - 1)

S7 = (4(2187 - 1))/2

S7 = (4 × 2.186)/2

S7 = 2 × 2.186

S7 = 4.374

Nomor 2b

128 + 64 + 32

a = 128

r = 64 ÷ 128 = 0,5

S7 = (128(1 - 0,5^7)) / (1 - 0,5)

S7 = (128(1 - 0,008)) / (0, 5)

S7 = (128 × 0,99) / (0, 5)

S7 = 126,97/ 0,5

S7 = 253,94

Nomor 1a1 + 5 + 9 + 13 + ...a = 1b = 5 - 1 = 4S12 = 12/2 × (2(1) + (12 - 1) 4)S12 = 6 × (2 + 11 × 4)S12 = 6 × (2 + 44)S12 = 6 × 46S12 = 276Nomor 1b20 + 16 + 12a = 20b = 16 - 20 = -4S12 = 12/2 × (2(20) + (12 - 1) (-4)) S12 = 6 × (40 + 11 × (-4)) S12 = 6 × (40 - 44) S12 = 6 × (-4) S12 = -24Nomor 2a4 + 12 + 36a = 4r = 12/4 = 3S7 = (4(3^7 - 1))/(3 - 1) S7 = (4(2187 - 1))/2S7 = (4 × 2.186)/2S7 = 2 × 2.186S7 = 4.374Nomor 2b128 + 64 + 32a = 128r = 64 ÷ 128 = 0,5S7 = (128(1 - 0,5^7)) / (1 - 0,5) S7 = (128(1 - 0,008)) / (0, 5) S7 = (128 × 0,99) / (0, 5) S7 = 126,97/ 0,5S7 = 253,94Nomor 1a1 + 5 + 9 + 13 + ...a = 1b = 5 - 1 = 4S12 = 12/2 × (2(1) + (12 - 1) 4)S12 = 6 × (2 + 11 × 4)S12 = 6 × (2 + 44)S12 = 6 × 46S12 = 276Nomor 1b20 + 16 + 12a = 20b = 16 - 20 = -4S12 = 12/2 × (2(20) + (12 - 1) (-4)) S12 = 6 × (40 + 11 × (-4)) S12 = 6 × (40 - 44) S12 = 6 × (-4) S12 = -24Nomor 2a4 + 12 + 36a = 4r = 12/4 = 3S7 = (4(3^7 - 1))/(3 - 1) S7 = (4(2187 - 1))/2S7 = (4 × 2.186)/2S7 = 2 × 2.186S7 = 4.374Nomor 2b128 + 64 + 32a = 128r = 64 ÷ 128 = 0,5S7 = (128(1 - 0,5^7)) / (1 - 0,5) S7 = (128(1 - 0,008)) / (0, 5) S7 = (128 × 0,99) / (0, 5) S7 = 126,97/ 0,5S7 = 253,94Nomor 1a1 + 5 + 9 + 13 + ...a = 1b = 5 - 1 = 4S12 = 12/2 × (2(1) + (12 - 1) 4)S12 = 6 × (2 + 11 × 4)S12 = 6 × (2 + 44)S12 = 6 × 46S12 = 276Nomor 1b20 + 16 + 12a = 20b = 16 - 20 = -4S12 = 12/2 × (2(20) + (12 - 1) (-4)) S12 = 6 × (40 + 11 × (-4)) S12 = 6 × (40 - 44) S12 = 6 × (-4) S12 = -24Nomor 2a4 + 12 + 36a = 4r = 12/4 = 3S7 = (4(3^7 - 1))/(3 - 1) S7 = (4(2187 - 1))/2S7 = (4 × 2.186)/2S7 = 2 × 2.186S7 = 4.374Nomor 2b128 + 64 + 32a = 128r = 64 ÷ 128 = 0,5S7 = (128(1 - 0,5^7)) / (1 - 0,5) S7 = (128(1 - 0,008)) / (0, 5) S7 = (128 × 0,99) / (0, 5) S7 = 126,97/ 0,5S7 = 253,94

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Last Update: Thu, 27 Oct 22
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