Jawaban:

Luas permukaan balok tanpa tutup adalah = 248 cm²

Penjelasan:

diketahui: Balok tanpa tutup

Panjang ( P ) = 10 cm

Lebar ( L ) = 6 cm

Tinggi ( T ) = 4 cm

Ditanya :

L.Permukaan ( LP ) balok tanpa tutup =....cm²

Jawab :

L.P = ( P × L ) + ( 2×( P × T ) + ( L × T ) )

= ( 10 cm × 6 cm ) + ( 2× (10 cm × 4 cm ) + ( 6 × 4 ) )

= ( 60 cm )+ (2× ( 40 cm + 24 cm ) )

= 60 + (2 × 64 )

= 60 + 128

= 188 cm²

Jadi luas permukaan balok tanpa tutup adalah: ( P × L ) +( 2× ( P × T ) + ( L × T ) ) = ( 10 × 6 ) + ( 2×( 10 × 4 ) + ( 6 × 4 ) ) = ( 60 ) + ( 2×(40 + 24 ) = 60 + ( 2 × 64 ) = 60 + 128 cm²

Answer by : AvrilKimWiguna

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