Jawaban:

✍ Penyelesaian

Jika:

f(x) = x(x!)² + 19x³ + 4x²

Maka:

f(2) = 2(2!)² + 19(2)³ + 4(2)²

f(2) = 2(2 × 1)² + 19(2 × 2 × 2) + 4(2 × 2)

f(2) = 2(2)² + 19(4 × 2) + 4(4)

f(2) = 2(2 × 2) + 19(8) + 16

f(2) = 2(4) + 152 + 16

f(2) = 8 + 152 + 16

f(2) = 160 + 16

f(2) = 176

f(3) = 3(3!)² + 19(3)³ + 4(3)²

f(3) = 3(3 × 2 × 1)² + 19(3 × 3 × 3) + 4(3 × 3)

f(3) = 3(6 × 1) + 19(9 × 3) + 4(9)

f(3) = 3(6)² + 19(27) + 36

f(3) = 3(6 × 6) + 513 + 36

f(3) = 3(36) + 513 + 36

f(3) = 108 + 513 + 36

f(3) = 621 + 36

f(3) = 657