tentukan penyelesaian spldv dg cara grafik dan substitusi1. 5x +

Berikut ini adalah pertanyaan dari nimariani27 pada mata pelajaran Matematika untuk jenjang Sekolah Menengah Pertama

Tentukan penyelesaian spldv dg cara grafik dan substitusi1. 5x + 2y = -10 dan x -3y = -19
2. 7x - 4y = 35 dan 3x + 5y = -32
pke cara
klo g tau jgn jwb

Jawaban dan Penjelasan

Berikut ini adalah pilihan jawaban terbaik dari pertanyaan diatas.

Materi : SPLDV

Soal Nomor 1

5x + 2y = -10

[ x = 0, y = -5 ] [ y = 0, x = -2 ]

x - 3y = -19

[ x = 0, y = 19/3 ] [ y = 0, x = -19 ]

[ Metode Substitusi ] ( - 4 , 6,... )

Nilai y

x = 3y + 19

5( 3y + 19 ) + 2y = -10

15y + 95 + 2y = -10

17y = 105

y = 105/7

Nilai x

3y = x + 19

5x + ⅔( x + 19 ) = -10

15x + 2( x + 19 ) = -30

15x + 2x + 38 = -30

17x = -68

x = -68/17

x = -4

Soal Nomor 2

7x - 4y = 35

[ x = 0, y = -8,75 ] [ y = 0, x = 5 ]

3x + 5y = -32

[ x = 0, y = -6,4 ] [ y = 0, x = -10,66 ]

[ Metode Substitusi ] ( 1 , -7 )

Nilai x

4y = 7x - 35

3x + ( 5/4 )( 7x - 35 ) = -32

12x + 5( 7x - 35 ) = -128

12x + 35x - 175 = -128

47x = 47

x = 1

Nilai y

3x = - 5y - 32

(7/3)( - 5y - 32 ) - 4y = 35

7( - 5y - 32 ) - 12y = 105

- 35y - 224 - 12y = 105

47y = -329

y = - 329/47

y = -7

Metode Grafik ( 1 & 2 )

Gambar yang Terlampirkan

Semoga bisa membantu

$\boxed{ \colorbox{navy}{ \sf{ \color{lightblue}{ Answer\:by\: BLUEBRAXGEOMETRY}}}}$

$Materi : SPLDVSoal Nomor 1 5x + 2y = -10[ x = 0, y = -5 ] [ y = 0, x = -2 ]x - 3y = -19[ x = 0, y = 19/3 ] [ y = 0, x = -19 ][ Metode Substitusi ] ( - 4 , 6,... )Nilai y x = 3y + 19 5( 3y + 19 ) + 2y = -1015y + 95 + 2y = -1017y = 105y = 105/7 Nilai x 3y = x + 195x + ⅔( x + 19 ) = -1015x + 2( x + 19 ) = -3015x + 2x + 38 = -3017x = -68x = -68/17x = -4Soal Nomor 2 7x - 4y = 35[ x = 0, y = -8,75 ] [ y = 0, x = 5 ]3x + 5y = -32[ x = 0, y = -6,4 ] [ y = 0, x = -10,66 ][ Metode Substitusi ] ( 1 , -7 )Nilai x 4y = 7x - 353x + ( 5/4 )( 7x - 35 ) = -3212x + 5( 7x - 35 ) = -12812x + 35x - 175 = -12847x = 47x = 1Nilai y 3x = - 5y - 32(7/3)( - 5y - 32 ) - 4y = 357( - 5y - 32 ) - 12y = 105- 35y - 224 - 12y = 10547y = -329y = - 329/47y = -7Metode Grafik ( 1 & 2 ) Gambar yang Terlampirkan Semoga bisa membantu[tex] \boxed{ \colorbox{navy}{ \sf{ \color{lightblue}{ Answer\:by\: BLUEBRAXGEOMETRY}}}} [/tex]$ $Materi : SPLDVSoal Nomor 1 5x + 2y = -10[ x = 0, y = -5 ] [ y = 0, x = -2 ]x - 3y = -19[ x = 0, y = 19/3 ] [ y = 0, x = -19 ][ Metode Substitusi ] ( - 4 , 6,... )Nilai y x = 3y + 19 5( 3y + 19 ) + 2y = -1015y + 95 + 2y = -1017y = 105y = 105/7 Nilai x 3y = x + 195x + ⅔( x + 19 ) = -1015x + 2( x + 19 ) = -3015x + 2x + 38 = -3017x = -68x = -68/17x = -4Soal Nomor 2 7x - 4y = 35[ x = 0, y = -8,75 ] [ y = 0, x = 5 ]3x + 5y = -32[ x = 0, y = -6,4 ] [ y = 0, x = -10,66 ][ Metode Substitusi ] ( 1 , -7 )Nilai x 4y = 7x - 353x + ( 5/4 )( 7x - 35 ) = -3212x + 5( 7x - 35 ) = -12812x + 35x - 175 = -12847x = 47x = 1Nilai y 3x = - 5y - 32(7/3)( - 5y - 32 ) - 4y = 357( - 5y - 32 ) - 12y = 105- 35y - 224 - 12y = 10547y = -329y = - 329/47y = -7Metode Grafik ( 1 & 2 ) Gambar yang Terlampirkan Semoga bisa membantu[tex] \boxed{ \colorbox{navy}{ \sf{ \color{lightblue}{ Answer\:by\: BLUEBRAXGEOMETRY}}}} [/tex]$ $Materi : SPLDVSoal Nomor 1 5x + 2y = -10[ x = 0, y = -5 ] [ y = 0, x = -2 ]x - 3y = -19[ x = 0, y = 19/3 ] [ y = 0, x = -19 ][ Metode Substitusi ] ( - 4 , 6,... )Nilai y x = 3y + 19 5( 3y + 19 ) + 2y = -1015y + 95 + 2y = -1017y = 105y = 105/7 Nilai x 3y = x + 195x + ⅔( x + 19 ) = -1015x + 2( x + 19 ) = -3015x + 2x + 38 = -3017x = -68x = -68/17x = -4Soal Nomor 2 7x - 4y = 35[ x = 0, y = -8,75 ] [ y = 0, x = 5 ]3x + 5y = -32[ x = 0, y = -6,4 ] [ y = 0, x = -10,66 ][ Metode Substitusi ] ( 1 , -7 )Nilai x 4y = 7x - 353x + ( 5/4 )( 7x - 35 ) = -3212x + 5( 7x - 35 ) = -12812x + 35x - 175 = -12847x = 47x = 1Nilai y 3x = - 5y - 32(7/3)( - 5y - 32 ) - 4y = 357( - 5y - 32 ) - 12y = 105- 35y - 224 - 12y = 10547y = -329y = - 329/47y = -7Metode Grafik ( 1 & 2 ) Gambar yang Terlampirkan Semoga bisa membantu[tex] \boxed{ \colorbox{navy}{ \sf{ \color{lightblue}{ Answer\:by\: BLUEBRAXGEOMETRY}}}} [/tex]$