Materi : Persamaan Garis Lurus

Soal Nomor 1

Gradien

3x - 2y = 2

2y = 3x - 2

y = (3/2)x - 1 [ Gradien / m = 3/2 ]

Langsung saja

Titik ( x¹ = 3 dan y¹ = -2 ) dan m = 3/2

keterangan : Tegak Lurus ( -1/m )

\____________________________/

y - y¹ = ( -1/m )( x - x¹ )

y + 2 = ( -1/[3/2] )( x - 3 )

y + 2 = - ⅔( x - 3 )

3( y + 2 ) = - 2( x - 3 )

3y + 6 = - 2x + 6

2x + 3y = 0

Soal Nomor 2

Gradien

Titik ( x¹ = -1 dan y¹ = 2 )

Titik ( x² = 1 dan y² = -2 )

\__________________/

m = ( y² - y¹ )/( x² - x¹ )

m = ( - 2 - 2 )/( 1 + 1 )

m = (-4)/2

m = -2

Langsung saja

Titik ( x¹ = 3 dan y¹ = 4 ) dan m = -2

keterangan : Tegak Lurus ( -1/m )

\__________________________/

y - y¹ = ( -1/m )( x - x¹ )

y - 4 = ( -1/[-2] )( x - 3 )

y - 4 = ½( x - 3 )

2( y - 4 ) = x - 3

2y - 8 = x - 3

x - 2y + 5 = 0

Semoga bisa membantu