Penjelasan dengan langkah-langkah:

Persamaan Kuadrat

.

Cara(1) ---> Pemfaktoran

x² + 2x - 3 = 0

x² + 3x - x - 3 = 0

x(x + 3) - (x + 3) = 0

(x - 1)(x + 3) = 0

Solusi ----> x¹ = 1 atau x² = -3

HP = { -3 , 1 }

___________

Cara(2) ---> Rumus ABC

x² + 2x - 3 = 0

a = 1 , b = 2 , dan c = -3

x¹'² = ( -b ± √b² - 4ac ) / 2a

x¹'² = ( -2 ± √2² - 4(1)(-3)) / 2(1)

x¹'² = ( -2 ± √(4 + 12))/2

x¹'² = ( -2 ± √16 )/2

Solusi;

x¹ = (-2 + √16)/2 = (-2+4)/2 = 2/2 = 1

x² = (-2 - √16)/2 = (-2-4)/2 = -6/2 = -3

HP = { -3 , 1 }

___________

Cara(3) ----> Melengkapi Kuadrat sempurna

x² + 2x - 3 = 0

a = 1 , b = 2 , dan c = -3

d = b/2a = 2/2(1) = 1

e = (c - b²/4a) = (-3 - 2²/4(1)) = (-3 - 4/4) = (-3-1)= -4

.

a(x + d)² = -e

(x + 1)² = 4

x + 1 = ±√4

Solusi;

x¹ = √4 - 1 = 2 - 1 = 1

x² = -√4 - 1 = -2 - 1 = -3

HP = { -3 , 1 }