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pliss kasih tau caranya step by stepkalau ga mau di

Berikut ini adalah pertanyaan dari atsiilahzulfaa210 pada mata pelajaran Matematika untuk jenjang Sekolah Menengah Pertama

Pliss kasih tau caranya step by stepkalau ga mau di jawabkan bisa tolong kasih tau caranya aja,atau ga beri 1 contoh dari soal yg urutan ke 5​
pliss kasih tau caranya step by stepkalau ga mau di jawabkan bisa tolong kasih tau caranya aja,atau ga beri 1 contoh dari soal yg urutan ke 5​

Jawaban dan Penjelasan

Berikut ini adalah pilihan jawaban terbaik dari pertanyaan diatas.

Jawaban:

contoh 1-10

1) p = 2

q = 1

p^{2} = p × p = 2 × 2 = 4

q^{2} = q × q = 1 × 1 = 1

c = p^{2} + q^{2} = 4 + 1 = 5

a = p^{2} - q^{2} = 4 - 1 = 3

b = 2pq = 2 × 2 × 1 = 4 × 1 = 4

hubungan c^{2} = a^{2} + b^{2}

c × c = (a × a) + (b × b)

5 × 5 = (3 × 3) + (4 × 4)

25 = 9 + 16

2) p = 3

q = 1

p^{2} = p × p = 3 × 3 = 9

q^{2} = q × q = 1 × 1 = 1

c = p^{2} + q^{2} = 9 + 1 = 10

a = p^{2} - q^{2} = 9 - 1 = 8

b = 2pq = 2 × 3 × 1 = 6 × 1 = 6

hubungan c^{2} = a^{2} + b^{2}

c × c = (a × a) + (b × b)

10 × 10 = (8 × 8) + (6 × 6)

100 = 64 + 36

3) p = 3

q = 2

p^{2} = p × p = 3 × 3 = 9

q^{2} = q × q = 2 × 2 = 4

c = p^{2} + q^{2} = 9 + 4 = 13

a = p^{2} - q^{2} = 9 - 4 = 5

b = 2pq = 2 × 3 × 2 = 6 × 2 = 12

hubungan c^{2} = a^{2} + b^{2}

c × c = (a × a) + (b × b)

13 × 13 = (5 × 5) + (12 × 12)

169 = 25 + 144

4) p = 4

q = 1

p^{2} = p × p = 4 × 4 = 16

q^{2} = q × q = 1 × 1 = 1

c = p^{2} + q^{2} = 16 + 1 = 17

a = p^{2} - q^{2} = 16 - 1 = 15

b = 2pq = 2 × 4 × 1 = 8 × 1 = 8

hubungan c^{2} = a^{2} + b^{2}

c × c = (a × a) + (b × b)

17 × 17 = (15 × 15) + (8 × 8)

289 = 225 + 64

5) p = 4

q = 2

p^{2} = p × p = 4 × 4 = 16

q^{2} = q × q = 2 × 2 = 4

c = p^{2} + q^{2} = 16 + 4 = 20

a = p^{2} - q^{2} = 16 - 4 = 12

b = 2pq = 2 × 4 × 2 = 8 × 2 = 16

hubungan c^{2} = a^{2} + b^{2}

c × c = (a × a) + (b × b)

20 × 20 = (12 × 12) + (16 × 16)

400 = 144 + 256

6) p = 4

q = 3

p^{2} = p × p = 4 × 4 = 16

q^{2} = q × q = 3 × 3 = 9

c = p^{2} + q^{2} = 16 + 9 = 25

a = p^{2} - q^{2} = 16 - 9 = 7

b = 2pq = 2 × 4 × 3 = 8 × 3 = 24

hubungan c^{2} = a^{2} + b^{2}

c × c = (a × a) + (b × b)

25 × 25 = (7 × 7) + (24 × 24)

625 = 49 + 576

7) p = 5

q = 1

p^{2} = p × p = 5 × 5 = 25

q^{2} = q × q = 1 × 1 = 1

c = p^{2} + q^{2} = 25 + 1 = 26

a = p^{2} - q^{2} = 25 - 1 = 24

b = 2pq = 2 × 5 × 1 = 10 × 1 = 10

hubungan c^{2} = a^{2} + b^{2}

c × c = (a × a) + (b × b)

26 × 26 = (24 × 24) + (10 × 10)

676 = 576 + 100

8) p = 5

q = 2

p^{2} = p × p = 5 × 5 = 25

q^{2} = q × q = 2 × 2 = 4

c = p^{2} + q^{2} = 25 + 4 = 29

a = p^{2} - q^{2} = 25 - 4 = 21

b = 2pq = 2 × 5 × 2 = 10 × 2 = 20

hubungan c^{2} = a^{2} + b^{2}

c × c = (a × a) + (b × b)

29 × 29 = (21 × 21) + (20 × 20)

841 = 441 + 400

9) p = 5

q = 3

p^{2} = p × p = 5 × 5 = 25

q^{2} = q × q = 3 × 3 = 9

c = p^{2} + q^{2} = 25 + 9 = 34

a = p^{2} - q^{2} = 25 - 9 = 16

b = 2pq = 2 × 5 × 3 = 10 × 3 = 30

hubungan c^{2} = a^{2} + b^{2}

c × c = (a × a) + (b × b)

34 × 34 = (16 × 16) + (30 × 30)

1156 = 256 + 900

10) p = 5

q = 4

p^{2} = p × p = 5 × 5 = 25

q^{2} = q × q = 4 × 4 = 16

c = p^{2} + q^{2} = 25 + 16 = 41

a = p^{2} - q^{2} = 25 - 16 = 9

b = 2pq = 2 × 5 × 4 = 10 × 4 = 40

hubungan c^{2} = a^{2} + b^{2}

c × c = (a × a) + (b × b)

41 × 41 = (9 × 9) + (40 × 40)

1681 = 81 + 1600

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Last Update: Wed, 12 Apr 23
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