Jawab:
a. (hogof)(3) = 4
b. ((goh)of)(3) = 5
c. (fo(goh))(2) = -15
d. ((gof)oh)(2) = 5

Penjelasan:
Diketahui
-->  f(x) = 2-x
--> g(x) = x²+1
--> h(x) = 2x

Hitunglah
a. (hogof)(3) = (h(g(f(3))))
= (h(g(2-3))) = (h(g(-1)))
= (h((-1)²+1)) = (h(1+1)) = (h(2))
= 2(2) = 4
Maka (hogof)(3) = 4

b. ((goh)of)(3) = ((g(h(x)))of)(3)
= ((g(2x))of)(3) = (((2x)²+1)of)(3)
= ((2²x²+1)of)(3) = ((4x²+1)of)(3)
= 4(f(3))²+1 = 4(2-3)²+1 = 4(-1)²+1
= 4(1)+1 = 4+1 = 5
Maka ((goh)of)(3) = 5

c. (fo(goh))(2) = fo(g(h(2))) =
fo(g(2(2))) = fo(g(4)) = fo(4²+1)
= fo(16+1) = fo(17) = f(17) =
2-17 = -(17-2) = -15
Maka (fo(goh))(2) = -15

d. ((gof)oh)(2) = ((g(f(x)))oh)(2) =
((g(2-x))oh)(2) = (((2-x)²+1)oh)(2) =
((2²-4x+x²+1)oh)(2) =
((4-4x+x²+1)oh)(2) = ((-4x+x²+5)oh)(2)
= (-4(2x)+(2x)²+5)(2) = -4(2(2))+(2(2))²+5
= -4(4)+4²+5 = 5
Maka ((gof)oh)(2) = 5

(Xcvi)