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plis bantu jawab trimakasih​

Berikut ini adalah pertanyaan dari bintangarthamoorty pada mata pelajaran Matematika untuk jenjang Sekolah Menengah Pertama

Plis bantu jawab trimakasih​
plis bantu jawab trimakasih​

Jawaban dan Penjelasan

Berikut ini adalah pilihan jawaban terbaik dari pertanyaan diatas.

5. (i)

\frac{6}{10} = \frac{8}{8 + a}

6( 8 + a ) = 10.8

48 + 6a = 80

6a = 80 - 64

6a = 16

a = 16/6 = 8/3 = 2,66 cm

(ii)

\frac{12}{9} = \frac{b}{6}

12.6 = 9b

72 = 9b

b = 8 cm

(iii)

\frac{10}{15} = \frac{c}{18}

10.18 = 15c

180 = 15c

c = 12 cm

(iv)

\frac{d}{42} = \frac{24}{ 36}

36d = 24.42

36d = 1008

d = 28 cm

6. (i)

\frac{8}{a} = \frac{9}{12}

8.12 = 9a

96 = 9a

a = 32/3 = 10,66 cm

(ii)

\frac{12}{21} = \frac{b}{ 14}

12.14 = 21b

168 = 21b

b = 8 cm

(iii)

\frac{12}{12 + c} = \frac{10}{15}

12.15 = 10( 12 + c )

180 = 120 + 10c

180 - 120 = 10c

60 = 10c

c = 6 cm

(iv)

\frac{d}{d + 12} = \frac{18}{24}

24d = 18(d + 12)

24d = 18d + 216

24d - 18d = 216

6d = 216

d = 36 cm

7. (i) Mencari a

\frac{20}{15} = \frac{a}{30}

20.30 = 15a

600 = 15a

a = 40 cm

Mencari b

\frac{15}{12} = \frac{30}{b}

15b = 12.30

15b = 360

b = 24 cm

Mencari c

\frac{20}{35} = \frac{c}{60}

20.60 = 35c

1200 = 35c

c = 240/7 = 34,28 cm

Mencari d

\frac{15}{27} = \frac{60}{d}

15d = 27.60

15d = 1620

d = 108 cm

(ii) Mencari a

\frac{6}{a} = \frac{4}{2}

6.2 = 4a

12 = 4a

a = 3 cm

Mencari b

\frac{b}{4} = \frac{6}{a} \\ \frac{b}{4} = \frac{6}{3}

3b = 6.4

3b = 24

b = 8 cm

Mencari c

\frac{4}{ 6} = \frac{3}{c}

4c = 6.3

4c = 18

c = 4,5 cm

Mencari d

\frac{8}{12} = \frac{d}{9}

8.9 = 12d

72 = 12d

d = 6 cm

8.

ef = \frac{(bf \times dc )+(cf \times ab) }{bf + fc} \\ = \frac{(4 \times 18) + (8 \times 15)}{4 + 8} \\ = \frac{72 + 120}{12} \\ = \frac{192}{12} \\ = 16 \: cm

9. AB = 15 cm, AD = 9 cm

a. AC = .....?

AB² = AD × AC

15² = 9AC

225 = 9AC

AC = 25 cm

b. DC = .....?

DC = AC - AD

= 25 - 9

= 16 cm

c. BD = ....?

BD² = AD × DC

= 9.16

= 144

BD = √144

= 12 cm

d. BC = .....?

BC² = DC × AC

= 16 × 25

= 400

BC = √400

= 20 cm

10. QS = 8 cm, L ΔQRS = 48 cm²

a. RS = ....?

L ΔQRS = ½.QS.RS( karena segitiga siku-siku)

48 = ½.6.RS

48 = 3RS

RS = 16 cm

b. PS = ....?

RS² = PS × QS

16² = PS × 8

256 = 8PS

PS = 32 cm

c. PR = .....?

PQ = PS + QS

= 32 + 8

= 40 cm

PR² = PS × PQ

= 32 × 40

= 1280

PR = √1280

= √(256.5)

= 16√5 cm

d. QR = ......?

QR² = SQ × PQ

= 8 × 40

= 320

QR = √320

= √(64.5)

= 8√5 cm

Semoga dengan pertanyaan yang sudah terjawab oleh zuhdim106 dapat membantu memudahkan mengerjakan soal, tugas dan PR sekolah kalian.

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Last Update: Thu, 27 Apr 23
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