Jawab:
[1]   n = -4
[2]  y = 1
[3]  p ≥ - 41
[4]  m > -2
[5]  m = {2, 4, 6, 8}
[6]  terbuka = (1) x + 5 = 9  (4) 2 + y = 11
[7]  x ≥ 1

Penjelasan:
[1]  2(2n-1)-6n = 6
2(2n)-2(1)-6n = 6
4n-2-6n = 6
6n-4n = -6-2
2n = -8
n = -8/2
n = -4

[2]  ¼ (5y – 1) = ⅓ (2y + 1)
4(2y+1) = 3(5y-1)
4(2y)+4(1) = 3(5y)-3(1)
8y + 4 = 15y - 3
15y - 8y = 4 + 3
7y = 7
y = 7/7
y = 1

[3]  5p ≤ 3(2p + 7) + 20
5p ≤ 3(2p) + 3(7) + 20
5p ≤ 6p + 21 + 20
- 21 - 20 ≤ 6p - 5p
- 41 ≤ p
p ≥ - 41

[4]  2(m-3) > m-8
2(m)-2(3) > m-8
2m - 6 > m - 8
2m - m > 6 - 8
m > -2

[5]  m + 2 ≤ 11
m ≤ 11 - 2
m ≤ 9
m = {2, 4, 6, 8}

[6]  terbuka = belum diketahui
nilainya, seperti x dan y
(1) x + 5 = 9
(4) 2 + y = 11

[7]  ⅖(x + 1) ≥ ⅕ (x + 3)
2(x+1)(5) ≥ 5(x+3)
10(x+1) ≥ 5(x+3)
10x + 10 ≥ 5x + 5(3)
10x + 10 ≥ 5x + 15
10x - 5x ≥ 15 - 10
5x ≥ 5
x ≥ 5/5
x ≥ 1

(xcvi)