Jawaban:

1. a. 3 log 729

= 3 log 3⁶

= 3

b. ^(1/5) log 25√(5)

= ^(1/5) log 25.(5^(1/2))

= ^(1/5) log 25 + ^(1/5) log 5^(1/2)

= ^(5^-1) log 5^2 + ^(5^-1) log 5^(1/2)

= (2/-1)(^5 log 5) + (1/2 : -1)(^5 log 5)

= (-2)(1) + (-1/2)(1)

= -2 - 1/2

= -4/2 - 1/2

= -5/2

Jadi, nilai dari ^(1/5) log 25√(5) adalah -5/2.

2. a. 3^log 25× 1/5^log 81- 8^log 1/64

=3^log (5^2) x (5^-1)^log (3^4) - (2^3)^log (2^-6)

=(2/1) 3^log5 x (-4/1) 5^log3 - (-6/3) 2^log2

=2 x (-4) x (3^log5 x 5^log3) + (2 x 1)

= -8 x (3^log5 x 5^log3) + (2 x 1)

= -8 x 3^log 3 + 2

= -8 x 1 + 2

= -6

b. 7^log 1/49 + 5^log 2 × 8^log 125 - 1/27^log 9

=7^log(7^-2) + (5^log 2 x (2^3)^log (5^3)) - (3^-3)^log (3^2)

=-2 + (5^log 2 x 3/3 2^log5)- (-2/3 3^log 3)

=-2+(5^log 2 x 2^log 5) + 2/3 3^log3

=-2 + 5^log5 + 2/3.1

=-2 + 1 + 2/3

=-6/3 + 3/3 + 2/3

= -1/3

Jadi, hasil dari 7^log 1/49 + 5^log 2 × 8^log 125 - 1/27^log 9 adalah -1/3.

no 3 yg a dan b ada di gambar

4 a. Jawaban:

² log 49

²log7²

2 ²log 7

16 log 7 =p

2⁴ log 7 =p

1/4 ²log 7 = p

Penjelasan dengan langkah-langkah:

²log 7= 4p

maka

2 ²log 7

2(4p)

= 8p ✓