Quiz.[+15][tex] \\ [/tex][tex] \sf1. \: \: {45}^{2}

Berikut ini adalah pertanyaan dari Nelsyasj pada mata pelajaran Matematika untuk jenjang Sekolah Menengah Pertama

Quiz.[+15] $\\$
$\sf1. \: \: {45}^{2} + {75}^{2} = .. \\ \sf2. \: \: {66}^{2} + {99}^{2} = ..$

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Jawaban dan Penjelasan

Berikut ini adalah pilihan jawaban terbaik dari pertanyaan diatas.

Nomor 1

$\: \: \: \: {45}^{2} + {75 }^{2} \\ = (45 \times 45) + (75 \times 75) \\ = 2.025 + 5.625 \\ = 7.650$

Nomor 2

$\: \: \: \: {66}^{2} + {99}^{2} \\ = (66 \times 66) + (99 \times 99) \\ = 4.356 + 9.801 \\ = 14.157$

_______________________

Pengertian dari bilangan berpangkat dapat disimak pada link berikut : yomemimo.com/tugas/6661348

$pendahuluanbilangan berpangkat adalah bilangan berpangkat yang dikalikan secara berulang ulangsifat bilangan berpangkat[tex]\sf\:a^n×a^m=a^{n+m}[/tex]a^n×a^m=a^{n+m}[tex]\sf {a}^{m} \div {a}^{n} = {a}^{m - n}[/tex]am÷an=am−nam÷an=am−nam÷an=am−n[tex]\sf( {a}^{n} ) {}^{m} = {a}^{n \times m}[/tex](an)m=an×m(an)m=an×m(an)m=an×m[tex]\sf {(a \times b)}^{n} = {a}^{n} \times {b}^{n}[/tex](a×b)n=an×bn(a×b)n=an×bn(a×b)n=an×bn[tex]\sf {(a \div b)}^{m} = \frac{ {a}^{m} }{ {b}^{m} }[/tex](a÷b)m=bmam(a÷b)m=bmam(a÷b)m=bmam[tex]\sf \sqrt[n]{ {a}^{m} } = {a}^{ \frac{m}{n} }[/tex]nam=anmnam=anmnam=anm[tex]\sf {a}^{0} = [/tex]1a0=1a0=1a0=1[tex]\sf {a}^{1} = [/tex]aa1=aa1=aa1=aContoh Perpangkatan 2:1² = 1 × 1 = 12² = 2 × 2 = 43² = 3 × 3 = 94² = 4 × 4 = 165² = 5 × 5 = 256² = 6 × 6 = 367² = 7 × 7 = 498² = 8 × 8 = 649² = 9 × 9 = 8110² = 10 × 10 = 100Contoh Perpangkatan 3:1³ = 1 × 1 × 1 = 12³ = 2 × 2 × 2 = 83³ = 3 × 3 × 3 = 274³ = 4 × 4 × 4 = 645³ = 5 × 5 × 5 = 1246³ = 6 × 6 × 6 = 2167³ = 7 × 7 × 7 = 3438³ = 8 × 8 × 8 = 5129³ = 9 × 9 × 9 = 72910³ = 10 × 10 × 10 = 1.000Contoh Perpangkatan 4:1³ = 1 × 1 × 1 × 1 = 42⁴ = 2 × 2 × 2 × 2 = 163⁴ = 3 × 3 × 3 × 3 = 814⁴ = 4 × 4 × 4 × 4 = 2565⁴ = 5 × 5 × 5 × 5 = 6256⁴ = 6 × 6 × 6 × 6 = 1.2967⁴ = 7 × 7 × 7 × 7 = 2.4018⁴ = 8 × 8 × 8 × 8 = 4.0969⁴ = 9 × 9 × 9 × 9 = = 6.56110⁴ = 10 × 10 × 10 × 10 = 10.000Contoh Perpangkatan 5:1⁵ = 1 × 1 × 1 × 1 × 1 = 12⁵ = 2 × 2 × 2 × 2 × 2 = 323⁵ = 3 × 3 × 3 × 3 × 3 = 2434⁵ = 4 × 4 × 4 × 4 × 4 = 1.0245⁵ = 5 × 5 × 5 × 5 × 5 = 3.1256⁵ = 6 × 6 × 6 × 6 × 6 = 7.7767⁵ = 7 × 7 × 7 × 7 × 7 = 16.8078⁵ = 8 × 8 × 8 × 8 × 8 = 32.7689⁵ = 9 × 9 × 9 × 9 × 9 = 59.04910⁵ = 10 × 10 × 10 × 10 × 10 = 100.000pembahasansoal no 1[tex] \gg \sf \: \: {45}^{2} + {75}^{2} =[/tex][tex] \to \sf(45 \times 45) + (75 \times 75) = [/tex][tex] \to \sf2.025 + 5.625 = [/tex][tex] \Rightarrow \sf \underline{7.650}[/tex]soal no 2[tex] \gg \sf{66}^{2} + {99}^{2} =[/tex][tex] \to \sf(66 \times 66) + (99 \times 99) = [/tex][tex] \to \sf4.356 + 9.801 = [/tex][tex] \Rightarrow \sf \underline{14.157}[/tex]pelajari lebih lanjutuntuk cara mengoperasikan eksponen ada di linkhttps://brainly.co.id/buku-sekolah/b-matematika-3-untuk-smp-mts-kelas-ix-9786024347437https://brainly.co.id/tugas/48825022detail jawaban❐kelas : 9 smp❐mapel : matematika❐bab : 1 pangkat(eksponen)bilangan bulat dan bentuk akar❐kata kunci : eksponen$ $pendahuluanbilangan berpangkat adalah bilangan berpangkat yang dikalikan secara berulang ulangsifat bilangan berpangkat[tex]\sf\:a^n×a^m=a^{n+m}[/tex]a^n×a^m=a^{n+m}[tex]\sf {a}^{m} \div {a}^{n} = {a}^{m - n}[/tex]am÷an=am−nam÷an=am−nam÷an=am−n[tex]\sf( {a}^{n} ) {}^{m} = {a}^{n \times m}[/tex](an)m=an×m(an)m=an×m(an)m=an×m[tex]\sf {(a \times b)}^{n} = {a}^{n} \times {b}^{n}[/tex](a×b)n=an×bn(a×b)n=an×bn(a×b)n=an×bn[tex]\sf {(a \div b)}^{m} = \frac{ {a}^{m} }{ {b}^{m} }[/tex](a÷b)m=bmam(a÷b)m=bmam(a÷b)m=bmam[tex]\sf \sqrt[n]{ {a}^{m} } = {a}^{ \frac{m}{n} }[/tex]nam=anmnam=anmnam=anm[tex]\sf {a}^{0} = [/tex]1a0=1a0=1a0=1[tex]\sf {a}^{1} = [/tex]aa1=aa1=aa1=aContoh Perpangkatan 2:1² = 1 × 1 = 12² = 2 × 2 = 43² = 3 × 3 = 94² = 4 × 4 = 165² = 5 × 5 = 256² = 6 × 6 = 367² = 7 × 7 = 498² = 8 × 8 = 649² = 9 × 9 = 8110² = 10 × 10 = 100Contoh Perpangkatan 3:1³ = 1 × 1 × 1 = 12³ = 2 × 2 × 2 = 83³ = 3 × 3 × 3 = 274³ = 4 × 4 × 4 = 645³ = 5 × 5 × 5 = 1246³ = 6 × 6 × 6 = 2167³ = 7 × 7 × 7 = 3438³ = 8 × 8 × 8 = 5129³ = 9 × 9 × 9 = 72910³ = 10 × 10 × 10 = 1.000Contoh Perpangkatan 4:1³ = 1 × 1 × 1 × 1 = 42⁴ = 2 × 2 × 2 × 2 = 163⁴ = 3 × 3 × 3 × 3 = 814⁴ = 4 × 4 × 4 × 4 = 2565⁴ = 5 × 5 × 5 × 5 = 6256⁴ = 6 × 6 × 6 × 6 = 1.2967⁴ = 7 × 7 × 7 × 7 = 2.4018⁴ = 8 × 8 × 8 × 8 = 4.0969⁴ = 9 × 9 × 9 × 9 = = 6.56110⁴ = 10 × 10 × 10 × 10 = 10.000Contoh Perpangkatan 5:1⁵ = 1 × 1 × 1 × 1 × 1 = 12⁵ = 2 × 2 × 2 × 2 × 2 = 323⁵ = 3 × 3 × 3 × 3 × 3 = 2434⁵ = 4 × 4 × 4 × 4 × 4 = 1.0245⁵ = 5 × 5 × 5 × 5 × 5 = 3.1256⁵ = 6 × 6 × 6 × 6 × 6 = 7.7767⁵ = 7 × 7 × 7 × 7 × 7 = 16.8078⁵ = 8 × 8 × 8 × 8 × 8 = 32.7689⁵ = 9 × 9 × 9 × 9 × 9 = 59.04910⁵ = 10 × 10 × 10 × 10 × 10 = 100.000pembahasansoal no 1[tex] \gg \sf \: \: {45}^{2} + {75}^{2} =[/tex][tex] \to \sf(45 \times 45) + (75 \times 75) = [/tex][tex] \to \sf2.025 + 5.625 = [/tex][tex] \Rightarrow \sf \underline{7.650}[/tex]soal no 2[tex] \gg \sf{66}^{2} + {99}^{2} =[/tex][tex] \to \sf(66 \times 66) + (99 \times 99) = [/tex][tex] \to \sf4.356 + 9.801 = [/tex][tex] \Rightarrow \sf \underline{14.157}[/tex]pelajari lebih lanjutuntuk cara mengoperasikan eksponen ada di linkhttps://brainly.co.id/buku-sekolah/b-matematika-3-untuk-smp-mts-kelas-ix-9786024347437https://brainly.co.id/tugas/48825022detail jawaban❐kelas : 9 smp❐mapel : matematika❐bab : 1 pangkat(eksponen)bilangan bulat dan bentuk akar❐kata kunci : eksponen$ $pendahuluanbilangan berpangkat adalah bilangan berpangkat yang dikalikan secara berulang ulangsifat bilangan berpangkat[tex]\sf\:a^n×a^m=a^{n+m}[/tex]a^n×a^m=a^{n+m}[tex]\sf {a}^{m} \div {a}^{n} = {a}^{m - n}[/tex]am÷an=am−nam÷an=am−nam÷an=am−n[tex]\sf( {a}^{n} ) {}^{m} = {a}^{n \times m}[/tex](an)m=an×m(an)m=an×m(an)m=an×m[tex]\sf {(a \times b)}^{n} = {a}^{n} \times {b}^{n}[/tex](a×b)n=an×bn(a×b)n=an×bn(a×b)n=an×bn[tex]\sf {(a \div b)}^{m} = \frac{ {a}^{m} }{ {b}^{m} }[/tex](a÷b)m=bmam(a÷b)m=bmam(a÷b)m=bmam[tex]\sf \sqrt[n]{ {a}^{m} } = {a}^{ \frac{m}{n} }[/tex]nam=anmnam=anmnam=anm[tex]\sf {a}^{0} = [/tex]1a0=1a0=1a0=1[tex]\sf {a}^{1} = [/tex]aa1=aa1=aa1=aContoh Perpangkatan 2:1² = 1 × 1 = 12² = 2 × 2 = 43² = 3 × 3 = 94² = 4 × 4 = 165² = 5 × 5 = 256² = 6 × 6 = 367² = 7 × 7 = 498² = 8 × 8 = 649² = 9 × 9 = 8110² = 10 × 10 = 100Contoh Perpangkatan 3:1³ = 1 × 1 × 1 = 12³ = 2 × 2 × 2 = 83³ = 3 × 3 × 3 = 274³ = 4 × 4 × 4 = 645³ = 5 × 5 × 5 = 1246³ = 6 × 6 × 6 = 2167³ = 7 × 7 × 7 = 3438³ = 8 × 8 × 8 = 5129³ = 9 × 9 × 9 = 72910³ = 10 × 10 × 10 = 1.000Contoh Perpangkatan 4:1³ = 1 × 1 × 1 × 1 = 42⁴ = 2 × 2 × 2 × 2 = 163⁴ = 3 × 3 × 3 × 3 = 814⁴ = 4 × 4 × 4 × 4 = 2565⁴ = 5 × 5 × 5 × 5 = 6256⁴ = 6 × 6 × 6 × 6 = 1.2967⁴ = 7 × 7 × 7 × 7 = 2.4018⁴ = 8 × 8 × 8 × 8 = 4.0969⁴ = 9 × 9 × 9 × 9 = = 6.56110⁴ = 10 × 10 × 10 × 10 = 10.000Contoh Perpangkatan 5:1⁵ = 1 × 1 × 1 × 1 × 1 = 12⁵ = 2 × 2 × 2 × 2 × 2 = 323⁵ = 3 × 3 × 3 × 3 × 3 = 2434⁵ = 4 × 4 × 4 × 4 × 4 = 1.0245⁵ = 5 × 5 × 5 × 5 × 5 = 3.1256⁵ = 6 × 6 × 6 × 6 × 6 = 7.7767⁵ = 7 × 7 × 7 × 7 × 7 = 16.8078⁵ = 8 × 8 × 8 × 8 × 8 = 32.7689⁵ = 9 × 9 × 9 × 9 × 9 = 59.04910⁵ = 10 × 10 × 10 × 10 × 10 = 100.000pembahasansoal no 1[tex] \gg \sf \: \: {45}^{2} + {75}^{2} =[/tex][tex] \to \sf(45 \times 45) + (75 \times 75) = [/tex][tex] \to \sf2.025 + 5.625 = [/tex][tex] \Rightarrow \sf \underline{7.650}[/tex]soal no 2[tex] \gg \sf{66}^{2} + {99}^{2} =[/tex][tex] \to \sf(66 \times 66) + (99 \times 99) = [/tex][tex] \to \sf4.356 + 9.801 = [/tex][tex] \Rightarrow \sf \underline{14.157}[/tex]pelajari lebih lanjutuntuk cara mengoperasikan eksponen ada di linkhttps://brainly.co.id/buku-sekolah/b-matematika-3-untuk-smp-mts-kelas-ix-9786024347437https://brainly.co.id/tugas/48825022detail jawaban❐kelas : 9 smp❐mapel : matematika❐bab : 1 pangkat(eksponen)bilangan bulat dan bentuk akar❐kata kunci : eksponen$ $pendahuluanbilangan berpangkat adalah bilangan berpangkat yang dikalikan secara berulang ulangsifat bilangan berpangkat[tex]\sf\:a^n×a^m=a^{n+m}[/tex]a^n×a^m=a^{n+m}[tex]\sf {a}^{m} \div {a}^{n} = {a}^{m - n}[/tex]am÷an=am−nam÷an=am−nam÷an=am−n[tex]\sf( {a}^{n} ) {}^{m} = {a}^{n \times m}[/tex](an)m=an×m(an)m=an×m(an)m=an×m[tex]\sf {(a \times b)}^{n} = {a}^{n} \times {b}^{n}[/tex](a×b)n=an×bn(a×b)n=an×bn(a×b)n=an×bn[tex]\sf {(a \div b)}^{m} = \frac{ {a}^{m} }{ {b}^{m} }[/tex](a÷b)m=bmam(a÷b)m=bmam(a÷b)m=bmam[tex]\sf \sqrt[n]{ {a}^{m} } = {a}^{ \frac{m}{n} }[/tex]nam=anmnam=anmnam=anm[tex]\sf {a}^{0} = [/tex]1a0=1a0=1a0=1[tex]\sf {a}^{1} = [/tex]aa1=aa1=aa1=aContoh Perpangkatan 2:1² = 1 × 1 = 12² = 2 × 2 = 43² = 3 × 3 = 94² = 4 × 4 = 165² = 5 × 5 = 256² = 6 × 6 = 367² = 7 × 7 = 498² = 8 × 8 = 649² = 9 × 9 = 8110² = 10 × 10 = 100Contoh Perpangkatan 3:1³ = 1 × 1 × 1 = 12³ = 2 × 2 × 2 = 83³ = 3 × 3 × 3 = 274³ = 4 × 4 × 4 = 645³ = 5 × 5 × 5 = 1246³ = 6 × 6 × 6 = 2167³ = 7 × 7 × 7 = 3438³ = 8 × 8 × 8 = 5129³ = 9 × 9 × 9 = 72910³ = 10 × 10 × 10 = 1.000Contoh Perpangkatan 4:1³ = 1 × 1 × 1 × 1 = 42⁴ = 2 × 2 × 2 × 2 = 163⁴ = 3 × 3 × 3 × 3 = 814⁴ = 4 × 4 × 4 × 4 = 2565⁴ = 5 × 5 × 5 × 5 = 6256⁴ = 6 × 6 × 6 × 6 = 1.2967⁴ = 7 × 7 × 7 × 7 = 2.4018⁴ = 8 × 8 × 8 × 8 = 4.0969⁴ = 9 × 9 × 9 × 9 = = 6.56110⁴ = 10 × 10 × 10 × 10 = 10.000Contoh Perpangkatan 5:1⁵ = 1 × 1 × 1 × 1 × 1 = 12⁵ = 2 × 2 × 2 × 2 × 2 = 323⁵ = 3 × 3 × 3 × 3 × 3 = 2434⁵ = 4 × 4 × 4 × 4 × 4 = 1.0245⁵ = 5 × 5 × 5 × 5 × 5 = 3.1256⁵ = 6 × 6 × 6 × 6 × 6 = 7.7767⁵ = 7 × 7 × 7 × 7 × 7 = 16.8078⁵ = 8 × 8 × 8 × 8 × 8 = 32.7689⁵ = 9 × 9 × 9 × 9 × 9 = 59.04910⁵ = 10 × 10 × 10 × 10 × 10 = 100.000pembahasansoal no 1[tex] \gg \sf \: \: {45}^{2} + {75}^{2} =[/tex][tex] \to \sf(45 \times 45) + (75 \times 75) = [/tex][tex] \to \sf2.025 + 5.625 = [/tex][tex] \Rightarrow \sf \underline{7.650}[/tex]soal no 2[tex] \gg \sf{66}^{2} + {99}^{2} =[/tex][tex] \to \sf(66 \times 66) + (99 \times 99) = [/tex][tex] \to \sf4.356 + 9.801 = [/tex][tex] \Rightarrow \sf \underline{14.157}[/tex]pelajari lebih lanjutuntuk cara mengoperasikan eksponen ada di linkhttps://brainly.co.id/buku-sekolah/b-matematika-3-untuk-smp-mts-kelas-ix-9786024347437https://brainly.co.id/tugas/48825022detail jawaban❐kelas : 9 smp❐mapel : matematika❐bab : 1 pangkat(eksponen)bilangan bulat dan bentuk akar❐kata kunci : eksponen$ $pendahuluanbilangan berpangkat adalah bilangan berpangkat yang dikalikan secara berulang ulangsifat bilangan berpangkat[tex]\sf\:a^n×a^m=a^{n+m}[/tex]a^n×a^m=a^{n+m}[tex]\sf {a}^{m} \div {a}^{n} = {a}^{m - n}[/tex]am÷an=am−nam÷an=am−nam÷an=am−n[tex]\sf( {a}^{n} ) {}^{m} = {a}^{n \times m}[/tex](an)m=an×m(an)m=an×m(an)m=an×m[tex]\sf {(a \times b)}^{n} = {a}^{n} \times {b}^{n}[/tex](a×b)n=an×bn(a×b)n=an×bn(a×b)n=an×bn[tex]\sf {(a \div b)}^{m} = \frac{ {a}^{m} }{ {b}^{m} }[/tex](a÷b)m=bmam(a÷b)m=bmam(a÷b)m=bmam[tex]\sf \sqrt[n]{ {a}^{m} } = {a}^{ \frac{m}{n} }[/tex]nam=anmnam=anmnam=anm[tex]\sf {a}^{0} = [/tex]1a0=1a0=1a0=1[tex]\sf {a}^{1} = [/tex]aa1=aa1=aa1=aContoh Perpangkatan 2:1² = 1 × 1 = 12² = 2 × 2 = 43² = 3 × 3 = 94² = 4 × 4 = 165² = 5 × 5 = 256² = 6 × 6 = 367² = 7 × 7 = 498² = 8 × 8 = 649² = 9 × 9 = 8110² = 10 × 10 = 100Contoh Perpangkatan 3:1³ = 1 × 1 × 1 = 12³ = 2 × 2 × 2 = 83³ = 3 × 3 × 3 = 274³ = 4 × 4 × 4 = 645³ = 5 × 5 × 5 = 1246³ = 6 × 6 × 6 = 2167³ = 7 × 7 × 7 = 3438³ = 8 × 8 × 8 = 5129³ = 9 × 9 × 9 = 72910³ = 10 × 10 × 10 = 1.000Contoh Perpangkatan 4:1³ = 1 × 1 × 1 × 1 = 42⁴ = 2 × 2 × 2 × 2 = 163⁴ = 3 × 3 × 3 × 3 = 814⁴ = 4 × 4 × 4 × 4 = 2565⁴ = 5 × 5 × 5 × 5 = 6256⁴ = 6 × 6 × 6 × 6 = 1.2967⁴ = 7 × 7 × 7 × 7 = 2.4018⁴ = 8 × 8 × 8 × 8 = 4.0969⁴ = 9 × 9 × 9 × 9 = = 6.56110⁴ = 10 × 10 × 10 × 10 = 10.000Contoh Perpangkatan 5:1⁵ = 1 × 1 × 1 × 1 × 1 = 12⁵ = 2 × 2 × 2 × 2 × 2 = 323⁵ = 3 × 3 × 3 × 3 × 3 = 2434⁵ = 4 × 4 × 4 × 4 × 4 = 1.0245⁵ = 5 × 5 × 5 × 5 × 5 = 3.1256⁵ = 6 × 6 × 6 × 6 × 6 = 7.7767⁵ = 7 × 7 × 7 × 7 × 7 = 16.8078⁵ = 8 × 8 × 8 × 8 × 8 = 32.7689⁵ = 9 × 9 × 9 × 9 × 9 = 59.04910⁵ = 10 × 10 × 10 × 10 × 10 = 100.000pembahasansoal no 1[tex] \gg \sf \: \: {45}^{2} + {75}^{2} =[/tex][tex] \to \sf(45 \times 45) + (75 \times 75) = [/tex][tex] \to \sf2.025 + 5.625 = [/tex][tex] \Rightarrow \sf \underline{7.650}[/tex]soal no 2[tex] \gg \sf{66}^{2} + {99}^{2} =[/tex][tex] \to \sf(66 \times 66) + (99 \times 99) = [/tex][tex] \to \sf4.356 + 9.801 = [/tex][tex] \Rightarrow \sf \underline{14.157}[/tex]pelajari lebih lanjutuntuk cara mengoperasikan eksponen ada di linkhttps://brainly.co.id/buku-sekolah/b-matematika-3-untuk-smp-mts-kelas-ix-9786024347437https://brainly.co.id/tugas/48825022detail jawaban❐kelas : 9 smp❐mapel : matematika❐bab : 1 pangkat(eksponen)bilangan bulat dan bentuk akar❐kata kunci : eksponen$

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