Materi : Persamaan Garis Lurus

Soal Nomor 7

Bagian A

Titik R( x¹ = -3 dan y¹ = -4 ) dan m = -2

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y - y¹ = m( x - x¹ )

y + 4 = -2( x + 3 )

y + 4 = - 2x - 6

[ y + 2x + 10 = 0 ]

Bagian B

Titik D( x¹ = -5 dan y¹ = 6 ) dan m = -1

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y - y¹ = m( x - x¹ )

y - 6 = -1( x + 5 )

y - 6 = - x - 5

y + x = 6 - 5

[ x + y = 1 ]

Soal Nomor 8

Bagian A

Titik ( x¹ = 6 dan y¹ = 0 )

Titik ( x² = 0 dan y² = -4 )

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( y - y¹ )/( y² - y¹ ) = ( x - x¹ )/( x² - x¹ )

( y - 0 )/( - 4 - 0 ) = ( x - 6 )/( 0 - 6 )

y/-4 = ( x - 6 )/-6

-6( y ) = -4( x - 6 )

- 6y = - 4x + 24

4x - 6y = 24

Semua dibagi 2

[ 2x - 3y = 12 ]

Bagian B

Titik ( x¹ = 3 dan y¹ = 0 )

Titik ( x² = 0 dan y² = 2 )

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( y - y¹ )/( y² - y¹ ) = ( x - x¹ )/( x² - x¹ )

( y - 0 )/( 2 - 0 ) = ( x - 3 )/( 0 - 3 )

y/2 = ( x - 3 )/-3

-3( y ) = 2( x - 3 )

- 3y = 2x - 6

[ 2x + 3y = 6 ]

Semoga bisa membantu