Materi : Bangun Ruang Sisi Lengkung

Soal Nomor 1

Bagian A

Volume Tabung

V = π × r² × t

V = 3,14 × 11 cm × 11 cm × 9,8 cm

V = 30,772 cm × 121 cm²

{ V = 3.723,412 cm³ }

Luas Permukaan Tabung

Lp = 2( π × r² ) + π × d × t

Lp = 2( 3,14 × 11² ) + 3,14 × 22 × 9,8

Lp = 2 × 3,14 × 121 cm² + 3,14 × 215,6 cm²

Lp = 3,14 × 242 cm² + 3,14 × 215,6 cm²

Lp = 3,14 × 457,6 cm²

{ Lp = 1.436,864 cm² }

Bagian B

Volume Tabung

V = π × r² × t

V = 3,14 × 13 cm × 13cm × 15,7 cm

V = 49,298 cm × 169 cm²

{ V = 8.331,362 cm³ }

Luas Permukaan Tabung

Lp = 2( π × r² ) + π × d × t

Lp = 2 × 3,14 × 13² + 3,14 × 26 × 15,7 cm

Lp = 3,14 × 338 cm² + 3,14 × 408,2 cm²

Lp = 3,14 × ( 338 cm² + 408,2 cm² )

Lp = 3,14 × 746,2 cm²

{ Lp = 2.343,068 cm² }

Soal Nomor 2

Volume Kerucut

V = ⅓ × π × r² × t

V = ⅓ × 3,14 × 9 cm × 9 cm × 15 cm

V = 3,14 × 3 cm × 135 cm²

V = 9,42 cm × 135 cm²

{ V = 1.271,7 cm³ }

Luas Permukaan Kerucut

Lp = π × r × ( r + s )

Lp = 3,14 × 9 cm × ( 9 cm + 15 cm )

Lp = 28,26 cm² × 24 cm

{ Lp = 678,24 cm³ }

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