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BIG POIN.ada tugas pr nih kalo bisa pake cara KALU

Berikut ini adalah pertanyaan dari ANDRAAGUSPANDUWINATA pada mata pelajaran Matematika untuk jenjang Sekolah Menengah Pertama

BIG POIN.ada tugas pr nih
kalo bisa pake cara

KALU ADA JAWAB PERTANYAAN INI DENGAN BENAR' DAN CEPAT SAYA KASIH JAWABAN TERJERDAS.
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BIG POIN.ada tugas pr nih kalo bisa pake cara KALU ADA JAWAB PERTANYAAN INI DENGAN BENAR' DAN CEPAT SAYA KASIH JAWABAN TERJERDAS.​

Jawaban dan Penjelasan

Berikut ini adalah pilihan jawaban terbaik dari pertanyaan diatas.

Jawaban:

Sistem Persamaan Garis Lurus (SPGL)

Penjelasan dengan langkah-langkah:

1. y=3x

x. y=3x. (x,y)

-5. y=3(-5)=-15. (-5,-15)

-4. y=3(-4)=-12. (-4,-12)

-3. y=3(-3)=-9. (-3,-9)

-2. y=3(-2)=-6. (-2,-6)

-1. y=3(-1)=-3. (-1,-3)

0. y=3(0)=0. (0,0)

1. y=3(1)=3. (1,3)

2. y=3(2)=6. (2,6)

3. y=3(3)=9. (3,9)

4. y=3(4)=12. (4,12)

5. y=3(5)=15. (5,15)

2. y=-3x

x. y=-3x. (x,y)

-5 y=-3(-5)=15. (-5,15)

-4. y=-3(-4)=12. (-4,12)

-3. y=-3(-3)=9. (-3,9)

-2. y=-3(-2)=6. (-2,6)

-1. y=-3(-1)=3. (-1,3)

0. y=-3(0)=0. (0,0)

1. y=-3(1)=-3. (1,-3)

2. y=-3(2)=-6. (2,-6)

3. y=-3(3)=-9. (3,-9)

4. y=-3(4)=-12. (4,-12)

5. y=-3(5)=-15. (5,-15)

3. y=1/2x

x. y=1/2x. (x,y)

-5. y=1/2(-5)=-5/2=-2 1/2 (-5,-2 1/2)

-4. y=1/2(-4)=-4/2=-2. (-4,-2)

-3. y=1/2(-3)=-3/2=-1 1/2. (-3,-1 1/2)

-2. y=1/2(-2)=-2/2=-1. (-2,-1)

-1. y=1/2(-1)=-1/2. (-1,-1/2)

0. y=1/2(0)=0. (0,0)

1. y=1/2(1)=1/2. (1,1/2)

2. y=1/2(2)=2/2=1. (2,1)

3. y=1/2(3)=3/2=1 1/2. (3,1 1/2)

4. y=1/2(4)=4/2=2. (4,2)

5. y=1/2(5)=5/2=2 1/2. (5,2 1/2)

4. y=-1/2x

x. y=-1/2x. (x,y)

-5. y=-1/2(-5)=5/2=2 1/2. (-5,2 1/2)

-4. y=-1/2(-4)=4/2=2. (-4,2)

-3. y=-1/2(-3)=3/2=1 1/2. (-3,1 1/2)

-2. y=-1/2(-2)=2/2=1. (-2,1)

-1. y=-1/2(-1)=1/2. (-1,1/2)

0. y=-1/2(0)=0. (0,0)

1. y=-1/2(1)=-1/2. (1,-1/2)

2. y=-1/2(2)=-2/2=-1. (2,-1)

3. y=-1/2(3)=-3/2=-1 1/2. (3,-1 1/2)

4. y=-1/2(4)=-4/2=-2. (4,-2)

5. y=-1/2(5)=-5/2=-2 1/2. (5,-2 1/2)

Untuk grafiknya hubungan setiap titik koordinat sesuai (x,y) terlampir.

Demikian

Semoga membantu dan bermanfaat!

Jawaban:Sistem Persamaan Garis Lurus (SPGL)Penjelasan dengan langkah-langkah:1. y=3x x. y=3x. (x,y) -5. y=3(-5)=-15. (-5,-15) -4. y=3(-4)=-12. (-4,-12) -3. y=3(-3)=-9. (-3,-9) -2. y=3(-2)=-6. (-2,-6) -1. y=3(-1)=-3. (-1,-3) 0. y=3(0)=0. (0,0) 1. y=3(1)=3. (1,3) 2. y=3(2)=6. (2,6) 3. y=3(3)=9. (3,9) 4. y=3(4)=12. (4,12) 5. y=3(5)=15. (5,15)2. y=-3x x. y=-3x. (x,y) -5 y=-3(-5)=15. (-5,15) -4. y=-3(-4)=12. (-4,12) -3. y=-3(-3)=9. (-3,9) -2. y=-3(-2)=6. (-2,6) -1. y=-3(-1)=3. (-1,3) 0. y=-3(0)=0. (0,0) 1. y=-3(1)=-3. (1,-3) 2. y=-3(2)=-6. (2,-6) 3. y=-3(3)=-9. (3,-9) 4. y=-3(4)=-12. (4,-12) 5. y=-3(5)=-15. (5,-15) 3. y=1/2x x. y=1/2x. (x,y) -5. y=1/2(-5)=-5/2=-2 1/2 (-5,-2 1/2) -4. y=1/2(-4)=-4/2=-2. (-4,-2) -3. y=1/2(-3)=-3/2=-1 1/2. (-3,-1 1/2) -2. y=1/2(-2)=-2/2=-1. (-2,-1) -1. y=1/2(-1)=-1/2. (-1,-1/2) 0. y=1/2(0)=0. (0,0) 1. y=1/2(1)=1/2. (1,1/2) 2. y=1/2(2)=2/2=1. (2,1) 3. y=1/2(3)=3/2=1 1/2. (3,1 1/2) 4. y=1/2(4)=4/2=2. (4,2) 5. y=1/2(5)=5/2=2 1/2. (5,2 1/2)4. y=-1/2x x. y=-1/2x. (x,y) -5. y=-1/2(-5)=5/2=2 1/2. (-5,2 1/2) -4. y=-1/2(-4)=4/2=2. (-4,2) -3. y=-1/2(-3)=3/2=1 1/2. (-3,1 1/2) -2. y=-1/2(-2)=2/2=1. (-2,1) -1. y=-1/2(-1)=1/2. (-1,1/2) 0. y=-1/2(0)=0. (0,0) 1. y=-1/2(1)=-1/2. (1,-1/2) 2. y=-1/2(2)=-2/2=-1. (2,-1) 3. y=-1/2(3)=-3/2=-1 1/2. (3,-1 1/2) 4. y=-1/2(4)=-4/2=-2. (4,-2) 5. y=-1/2(5)=-5/2=-2 1/2. (5,-2 1/2)Untuk grafiknya hubungan setiap titik koordinat sesuai (x,y) terlampir. DemikianSemoga membantu dan bermanfaat!Jawaban:Sistem Persamaan Garis Lurus (SPGL)Penjelasan dengan langkah-langkah:1. y=3x x. y=3x. (x,y) -5. y=3(-5)=-15. (-5,-15) -4. y=3(-4)=-12. (-4,-12) -3. y=3(-3)=-9. (-3,-9) -2. y=3(-2)=-6. (-2,-6) -1. y=3(-1)=-3. (-1,-3) 0. y=3(0)=0. (0,0) 1. y=3(1)=3. (1,3) 2. y=3(2)=6. (2,6) 3. y=3(3)=9. (3,9) 4. y=3(4)=12. (4,12) 5. y=3(5)=15. (5,15)2. y=-3x x. y=-3x. (x,y) -5 y=-3(-5)=15. (-5,15) -4. y=-3(-4)=12. (-4,12) -3. y=-3(-3)=9. (-3,9) -2. y=-3(-2)=6. (-2,6) -1. y=-3(-1)=3. (-1,3) 0. y=-3(0)=0. (0,0) 1. y=-3(1)=-3. (1,-3) 2. y=-3(2)=-6. (2,-6) 3. y=-3(3)=-9. (3,-9) 4. y=-3(4)=-12. (4,-12) 5. y=-3(5)=-15. (5,-15) 3. y=1/2x x. y=1/2x. (x,y) -5. y=1/2(-5)=-5/2=-2 1/2 (-5,-2 1/2) -4. y=1/2(-4)=-4/2=-2. (-4,-2) -3. y=1/2(-3)=-3/2=-1 1/2. (-3,-1 1/2) -2. y=1/2(-2)=-2/2=-1. (-2,-1) -1. y=1/2(-1)=-1/2. (-1,-1/2) 0. y=1/2(0)=0. (0,0) 1. y=1/2(1)=1/2. (1,1/2) 2. y=1/2(2)=2/2=1. (2,1) 3. y=1/2(3)=3/2=1 1/2. (3,1 1/2) 4. y=1/2(4)=4/2=2. (4,2) 5. y=1/2(5)=5/2=2 1/2. (5,2 1/2)4. y=-1/2x x. y=-1/2x. (x,y) -5. y=-1/2(-5)=5/2=2 1/2. (-5,2 1/2) -4. y=-1/2(-4)=4/2=2. (-4,2) -3. y=-1/2(-3)=3/2=1 1/2. (-3,1 1/2) -2. y=-1/2(-2)=2/2=1. (-2,1) -1. y=-1/2(-1)=1/2. (-1,1/2) 0. y=-1/2(0)=0. (0,0) 1. y=-1/2(1)=-1/2. (1,-1/2) 2. y=-1/2(2)=-2/2=-1. (2,-1) 3. y=-1/2(3)=-3/2=-1 1/2. (3,-1 1/2) 4. y=-1/2(4)=-4/2=-2. (4,-2) 5. y=-1/2(5)=-5/2=-2 1/2. (5,-2 1/2)Untuk grafiknya hubungan setiap titik koordinat sesuai (x,y) terlampir. DemikianSemoga membantu dan bermanfaat!Jawaban:Sistem Persamaan Garis Lurus (SPGL)Penjelasan dengan langkah-langkah:1. y=3x x. y=3x. (x,y) -5. y=3(-5)=-15. (-5,-15) -4. y=3(-4)=-12. (-4,-12) -3. y=3(-3)=-9. (-3,-9) -2. y=3(-2)=-6. (-2,-6) -1. y=3(-1)=-3. (-1,-3) 0. y=3(0)=0. (0,0) 1. y=3(1)=3. (1,3) 2. y=3(2)=6. (2,6) 3. y=3(3)=9. (3,9) 4. y=3(4)=12. (4,12) 5. y=3(5)=15. (5,15)2. y=-3x x. y=-3x. (x,y) -5 y=-3(-5)=15. (-5,15) -4. y=-3(-4)=12. (-4,12) -3. y=-3(-3)=9. (-3,9) -2. y=-3(-2)=6. (-2,6) -1. y=-3(-1)=3. (-1,3) 0. y=-3(0)=0. (0,0) 1. y=-3(1)=-3. (1,-3) 2. y=-3(2)=-6. (2,-6) 3. y=-3(3)=-9. (3,-9) 4. y=-3(4)=-12. (4,-12) 5. y=-3(5)=-15. (5,-15) 3. y=1/2x x. y=1/2x. (x,y) -5. y=1/2(-5)=-5/2=-2 1/2 (-5,-2 1/2) -4. y=1/2(-4)=-4/2=-2. (-4,-2) -3. y=1/2(-3)=-3/2=-1 1/2. (-3,-1 1/2) -2. y=1/2(-2)=-2/2=-1. (-2,-1) -1. y=1/2(-1)=-1/2. (-1,-1/2) 0. y=1/2(0)=0. (0,0) 1. y=1/2(1)=1/2. (1,1/2) 2. y=1/2(2)=2/2=1. (2,1) 3. y=1/2(3)=3/2=1 1/2. (3,1 1/2) 4. y=1/2(4)=4/2=2. (4,2) 5. y=1/2(5)=5/2=2 1/2. (5,2 1/2)4. y=-1/2x x. y=-1/2x. (x,y) -5. y=-1/2(-5)=5/2=2 1/2. (-5,2 1/2) -4. y=-1/2(-4)=4/2=2. (-4,2) -3. y=-1/2(-3)=3/2=1 1/2. (-3,1 1/2) -2. y=-1/2(-2)=2/2=1. (-2,1) -1. y=-1/2(-1)=1/2. (-1,1/2) 0. y=-1/2(0)=0. (0,0) 1. y=-1/2(1)=-1/2. (1,-1/2) 2. y=-1/2(2)=-2/2=-1. (2,-1) 3. y=-1/2(3)=-3/2=-1 1/2. (3,-1 1/2) 4. y=-1/2(4)=-4/2=-2. (4,-2) 5. y=-1/2(5)=-5/2=-2 1/2. (5,-2 1/2)Untuk grafiknya hubungan setiap titik koordinat sesuai (x,y) terlampir. DemikianSemoga membantu dan bermanfaat!Jawaban:Sistem Persamaan Garis Lurus (SPGL)Penjelasan dengan langkah-langkah:1. y=3x x. y=3x. (x,y) -5. y=3(-5)=-15. (-5,-15) -4. y=3(-4)=-12. (-4,-12) -3. y=3(-3)=-9. (-3,-9) -2. y=3(-2)=-6. (-2,-6) -1. y=3(-1)=-3. (-1,-3) 0. y=3(0)=0. (0,0) 1. y=3(1)=3. (1,3) 2. y=3(2)=6. (2,6) 3. y=3(3)=9. (3,9) 4. y=3(4)=12. (4,12) 5. y=3(5)=15. (5,15)2. y=-3x x. y=-3x. (x,y) -5 y=-3(-5)=15. (-5,15) -4. y=-3(-4)=12. (-4,12) -3. y=-3(-3)=9. (-3,9) -2. y=-3(-2)=6. (-2,6) -1. y=-3(-1)=3. (-1,3) 0. y=-3(0)=0. (0,0) 1. y=-3(1)=-3. (1,-3) 2. y=-3(2)=-6. (2,-6) 3. y=-3(3)=-9. (3,-9) 4. y=-3(4)=-12. (4,-12) 5. y=-3(5)=-15. (5,-15) 3. y=1/2x x. y=1/2x. (x,y) -5. y=1/2(-5)=-5/2=-2 1/2 (-5,-2 1/2) -4. y=1/2(-4)=-4/2=-2. (-4,-2) -3. y=1/2(-3)=-3/2=-1 1/2. (-3,-1 1/2) -2. y=1/2(-2)=-2/2=-1. (-2,-1) -1. y=1/2(-1)=-1/2. (-1,-1/2) 0. y=1/2(0)=0. (0,0) 1. y=1/2(1)=1/2. (1,1/2) 2. y=1/2(2)=2/2=1. (2,1) 3. y=1/2(3)=3/2=1 1/2. (3,1 1/2) 4. y=1/2(4)=4/2=2. (4,2) 5. y=1/2(5)=5/2=2 1/2. (5,2 1/2)4. y=-1/2x x. y=-1/2x. (x,y) -5. y=-1/2(-5)=5/2=2 1/2. (-5,2 1/2) -4. y=-1/2(-4)=4/2=2. (-4,2) -3. y=-1/2(-3)=3/2=1 1/2. (-3,1 1/2) -2. y=-1/2(-2)=2/2=1. (-2,1) -1. y=-1/2(-1)=1/2. (-1,1/2) 0. y=-1/2(0)=0. (0,0) 1. y=-1/2(1)=-1/2. (1,-1/2) 2. y=-1/2(2)=-2/2=-1. (2,-1) 3. y=-1/2(3)=-3/2=-1 1/2. (3,-1 1/2) 4. y=-1/2(4)=-4/2=-2. (4,-2) 5. y=-1/2(5)=-5/2=-2 1/2. (5,-2 1/2)Untuk grafiknya hubungan setiap titik koordinat sesuai (x,y) terlampir. DemikianSemoga membantu dan bermanfaat!Jawaban:Sistem Persamaan Garis Lurus (SPGL)Penjelasan dengan langkah-langkah:1. y=3x x. y=3x. (x,y) -5. y=3(-5)=-15. (-5,-15) -4. y=3(-4)=-12. (-4,-12) -3. y=3(-3)=-9. (-3,-9) -2. y=3(-2)=-6. (-2,-6) -1. y=3(-1)=-3. (-1,-3) 0. y=3(0)=0. (0,0) 1. y=3(1)=3. (1,3) 2. y=3(2)=6. (2,6) 3. y=3(3)=9. (3,9) 4. y=3(4)=12. (4,12) 5. y=3(5)=15. (5,15)2. y=-3x x. y=-3x. (x,y) -5 y=-3(-5)=15. (-5,15) -4. y=-3(-4)=12. (-4,12) -3. y=-3(-3)=9. (-3,9) -2. y=-3(-2)=6. (-2,6) -1. y=-3(-1)=3. (-1,3) 0. y=-3(0)=0. (0,0) 1. y=-3(1)=-3. (1,-3) 2. y=-3(2)=-6. (2,-6) 3. y=-3(3)=-9. (3,-9) 4. y=-3(4)=-12. (4,-12) 5. y=-3(5)=-15. (5,-15) 3. y=1/2x x. y=1/2x. (x,y) -5. y=1/2(-5)=-5/2=-2 1/2 (-5,-2 1/2) -4. y=1/2(-4)=-4/2=-2. (-4,-2) -3. y=1/2(-3)=-3/2=-1 1/2. (-3,-1 1/2) -2. y=1/2(-2)=-2/2=-1. (-2,-1) -1. y=1/2(-1)=-1/2. (-1,-1/2) 0. y=1/2(0)=0. (0,0) 1. y=1/2(1)=1/2. (1,1/2) 2. y=1/2(2)=2/2=1. (2,1) 3. y=1/2(3)=3/2=1 1/2. (3,1 1/2) 4. y=1/2(4)=4/2=2. (4,2) 5. y=1/2(5)=5/2=2 1/2. (5,2 1/2)4. y=-1/2x x. y=-1/2x. (x,y) -5. y=-1/2(-5)=5/2=2 1/2. (-5,2 1/2) -4. y=-1/2(-4)=4/2=2. (-4,2) -3. y=-1/2(-3)=3/2=1 1/2. (-3,1 1/2) -2. y=-1/2(-2)=2/2=1. (-2,1) -1. y=-1/2(-1)=1/2. (-1,1/2) 0. y=-1/2(0)=0. (0,0) 1. y=-1/2(1)=-1/2. (1,-1/2) 2. y=-1/2(2)=-2/2=-1. (2,-1) 3. y=-1/2(3)=-3/2=-1 1/2. (3,-1 1/2) 4. y=-1/2(4)=-4/2=-2. (4,-2) 5. y=-1/2(5)=-5/2=-2 1/2. (5,-2 1/2)Untuk grafiknya hubungan setiap titik koordinat sesuai (x,y) terlampir. DemikianSemoga membantu dan bermanfaat!

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Last Update: Sat, 27 May 23
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