Jawab:
Tinggi prisma (t) = 8 cm

Penjelasan:
Diketahui prisma (belah ketupat)
-->  diagonal a (a) = 16 cm
-->  diagonal b (b) = 12 cm
-->  Luas permukaan (L) = 512 cm²

Ditanya tinggi prisma (t)

Cari sisi miring alas (m)
m² = (a/2)² + (b/2)²
m² = (16/2)² + (12/2)²
m² = 8² + 6²
m² = 64 + 36
m² = 100
m = √100
m = 10 cm
-->  Sisi miring alas (m) = 10 cm

L = alas tutup        + selimutnya
L = (2×((a×b)/2)) + (t×(4×m))

t×(4×m) = L - (2×((a×b)/2))
t×(4×m) = L - (a×b)
t = (L - (a×b)) ÷ (4×m)
t = (512 - (16×12)) ÷ (4×10)
t = (512 - 192) ÷ 40
t = 320 ÷ 40
t = 8
-->  Tinggi prisma (t) = 8 cm

(xcvi)