1. In the diagram, LMN is a right-angled triangle. Three

Berikut ini adalah pertanyaan dari emelies132 pada mata pelajaran Matematika untuk jenjang Sekolah Menengah Pertama

1. In the diagram, LMN is a right-angled triangle. Three semicircles with diameters LN, NM and LM are drown. Given the areas of the semicircles A, B and C are 100.48 cm², 157 cm² and C cm². True or false length of LM is 12 cm? explain your answer.2. In the diagram, LMN is a right-angled triangle. Three semicircles with diameters LN, NM and LM are drown. Given the areas of the semicircles A, B and C are 100.48 cm², 157 cm² and C cm². Find the area of C.​
1. In the diagram, LMN is a right-angled triangle. Three semicircles with diameters LN, NM and LM are drown. Given the areas of the semicircles A, B and C are 100.48 cm², 157 cm² and C cm². True or false length of LM is 12 cm? explain your answer.2. In the diagram, LMN is a right-angled triangle. Three semicircles with diameters LN, NM and LM are drown. Given the areas of the semicircles A, B and C are 100.48 cm², 157 cm² and C cm². Find the area of C.​

Jawaban dan Penjelasan

Berikut ini adalah pilihan jawaban terbaik dari pertanyaan diatas.

Jawab:

Penjelasan dengan langkah-langkah:

Pythagoras

Given :

A area = 100,48 cm²

B area = 157 cm²

a) True or false length of LM is 12 cm? explain your answer.

So we should find a lenght of NM and AL first

ΔB = ¹/₂.¹/₄πd²

157 = ¹/₈.3,14.d²

d² = 157 ÷ 3,14 × ⁸/₁

d² = 400

d = √400

d = 20 cm  (NM'Length)

ΔA =  ¹/₂.¹/₄πd²

100,48 = ¹/₈.3,14.d²

d² = 100,48 ÷ 3,14 × ⁸/₁

d² = 256

d = √256

d =  16cm (AL'Lenght)

Then LM

LM² = NM² ₋ AL²

LM² = 400 - 256

LM² = 144

LM  = √144

LM  = 12 cm

∴  length of LM is 12 cm ( TRUE )

b) Area of C

ΔC = ¹/₂.3,14 × 6 × 6

    = 56,52 cm²

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Last Update: Tue, 20 Jun 23