Penjelasan dengan langkah-langkah:

SOAL REMEDIAL KELAS KU

1. Misal :

s = 10 cm

p = 8 cm

t = √(s² – p²)

t = √(10² – 8²)

t = √(100 – 64)

t = √36

t = 6 cm ✔

Jadi panjang sisi yang lain adalah 6 cm

2. d = 14 cm

π = 22/7

Keliling = π × d

Keliling = 22/7 × 14

Keliling = 22 × 14/7

Keliling = 22 × 2

Keliling = 44 cm ✔

3. Rata² = (42+46!47+43+48+49+47+47+46+45)/10

Rata² = 460

10

Rata² = 46 kg ✔

4. n(s) = 13

ganjil = { 1, 3, 5, 7, 9, 11, 13 }

genap = { 2, 4, 6, 8, 10, 12 }

n(genap) = 6

P(genap) = n(genap)

n(s)

P(genap) = 6 ✔

13

5. r1 = 8 cm

r2 = 3 cm

∆r = r1 – r2

∆r = 8 – 3

∆r = 5 cm

j = 13 cm

pgsL = √(j² – ∆r²)

pgsL = √(13² – 5²)

pgsL = √(169 – 25)

pgsL = √144

pgsL = 12 cm ✔

DETAIL JAWABAN :

M a t e r i : Uji Remedial

K e l a s : VIII

Semester : Genap

Kode Soal : Al-Khansa Islamic School