Jawab:

Penjelasan dengan langkah-langkah:

1. p = 12 cm; ℓ = 5 cm; t = 7 cm

Luas permukaan balok = (2 × p × ℓ) + (2 × p × t) + (2 × ℓ × t)

 = (2 × 12 cm × 5 cm) + (2 × 12 cm × 7 cm) + (2 × 5 cm × 7 cm)

 = 120 cm2 + 168 cm2 + 70 cm2

 = 358 cm2

Volume balok = p × ℓ × t

= 12 cm × 5 cm × 7 cm

= 420 cm3

2. p = 14 dm; ℓ = 10 dm; t = 8 dm

Luas permukaan balok = (2 × p × ℓ) + (2 × p × t) + (2 × ℓ × t)

 = (2 × 14 dm × 10 dm) + (2 × 14 dm × 8 dm) + (2 × 10 dm × 8 dm)

 = 280 dm2 + 224 dm2 + 160 dm2

 = 664 dm2

Volume balok = p × ℓ × t

 = 14 dm × 10 dm × 8 dm

 = 1.120 dm3 = 1.120 Liter

3. p = 11 cm; ℓ = 7 cm; t = 9 cm

Luas permukaan balok = (2 × p × ℓ) + (2 × p × t) + (2 × ℓ × t)

 = (2 × 11 cm × 7 cm) + (2 × 11 cm × 9 cm) + (2 × 7 cm × 9 cm)

 = 154 cm2 + 198 cm2 + 126 cm2

 = 478 cm2

Volume balok = p × ℓ × t

= 11 cm × 7 cm × 9 cm

= 693 cm3

4. p = 6 dm; ℓ = 3 dm; t = 4 dm

Luas permukaan balok = (2 × p × ℓ) + (2 × p × t) + (2 × ℓ × t)

 = (2 × 6 dm × 3 dm) + (2 × 6 dm × 4 dm) + (2 × 3 dm × 4 dm)

 = 36 dm2 + 48 dm2 + 24 dm2

 = 108 dm2

Volume balok = p × ℓ × t

 = 6 dm × 3 dm × 4 dm

 = 72 dm3 = 72 Liter

5. p = 18 cm; ℓ = 8 cm; t = 12 cm

Luas permukaan balok = (2 × p × ℓ) + (2 × p × t) + (2 × ℓ × t)

 = (2 × 18 cm × 8 cm) + (2 × 18 cm × 12 cm) + (2 × 8 cm × 12 cm)

 = 288 cm2 + 432 cm2 + 192 cm2

 = 912 cm2

Volume balok = p × ℓ × t

= 18 cm × 8 cm × 12 cm

= 1.728 cm3

6. p = 22 dm; ℓ = 14 dm; t = 18 dm

Luas permukaan balok = (2 × p × ℓ) + (2 × p × t) + (2 × ℓ × t)

 = (2 × 22 dm × 14 dm) + (2 × 22 dm × 18 dm) + (2 × 14 dm × 18 dm)

 = 616 dm2 + 792 dm2 + 504 dm2

 = 1.912 dm2

Volume balok = p × ℓ × t

 = 22 dm × 14 dm × 18 dm

 = 5.544 dm3 = 5.544 Liter

7. p = 22 cm; ℓ = 13 cm; t = 16 cm

Luas permukaan balok = (2 × p × ℓ) + (2 × p × t) + (2 × ℓ × t)

 = (2 × 22 cm × 13 cm) + (2 × 22 cm × 16 cm) + (2 × 13 cm × 16 cm)

 = 572 cm2 + 704 cm2 + 416 cm2

 = 1.692 cm2

Volume balok = p × ℓ × t

= 22 cm × 13 cm × 16 cm

= 4.576 cm3

8. p = 22 dm; ℓ = 10 dm; t = 14 dm

Luas permukaan balok = (2 × p × ℓ) + (2 × p × t) + (2 × ℓ × t)

 = (2 × 22 dm × 10 dm) + (2 × 22 dm × 14 dm) + (2 × 10 dm × 14 dm)

 = 440 dm2 + 616 dm2 + 280 dm2

 = 1.336 dm2

Volume balok = p × ℓ × t

 = 22 dm × 10 dm × 14 dm

 = 3.080 dm3 = 3.080 Liter