[tex] \\ [/tex]Jika:f(x) = x(x!)² + 19x³ + 4x² Maka:f(2)

Berikut ini adalah pertanyaan dari iimxnnr pada mata pelajaran Matematika untuk jenjang Sekolah Menengah Pertama

 \\ Jika:
f(x) = x(x!)² + 19x³ + 4x²
Maka:
f(2) = ...
f(3) = ...​
 \\
_.​

Jawaban dan Penjelasan

Berikut ini adalah pilihan jawaban terbaik dari pertanyaan diatas.

f(x) = x(x!)² + 19x³ + 4x²

f(2) = ...

f(3) = ...

f(2) = 2(2!)² + 19(2³) + 4(2²)

f(2) = 2(2 × 1)² + 19(2 × 2 × 2) + 4(2²)

f(2) = 2(2)² + 19(4 × 2) + 4(4)

f(2) = 2(4) + 19(8) + ( 4 × 4 )

f(2) = ( 2 × 4 ) + ( 19 × 8 ) + 16

f(2) = 8 + 152 + 16

f(2) = 160 + 16

f(2) = 176

f(3) = 3(3!)² + 19(3³) + 4(3²)

f(3) = 3(3 × 2 × 1)² + 19(3 × 3 × 3) + 4(3²)

f(3) = 3(6 × 1)² + 19(9 × 3) + 4(9)

f(3) = 3(6)² + 19(27) + ( 4 × 9 )

f(3) = 3(6 × 6) + 19(27) + 36

f(3) = 3(36) + ( 19 × 27 ) + 36

f(3) = ( 3 × 36 ) + 513 + 36

f(3) = 108 + 513 + 36

f(3) = 621 + 36

f(3) = 657

Jawaban:✍ PenyelesaianJika:f(x) = x(x!)² + 19x³ + 4x² Maka:f(2) = 2(2!)² + 19(2)³ + 4(2)²f(2) = 2(2 × 1)² + 19(2 × 2 × 2) + 4(2 × 2)f(2) = 2(2)² + 19(4 × 2) + 4(4)f(2) = 2(2 × 2) + 19(8) + 16f(2) = 2(4) + 152 + 16f(2) = 8 + 152 + 16f(2) = 160 + 16f(2) = 176f(3) = 3(3!)² + 19(3)³ + 4(3)²f(3) = 3(3 × 2 × 1)² + 19(3 × 3 × 3) + 4(3 × 3)f(3) = 3(6 × 1) + 19(9 × 3) + 4(9)f(3) = 3(6)² + 19(27) + 36f(3) = 3(6 × 6) + 513 + 36f(3) = 3(36) + 513 + 36f(3) = 108 + 513 + 36f(3) = 621 + 36f(3) = 657Jawaban:✍ PenyelesaianJika:f(x) = x(x!)² + 19x³ + 4x² Maka:f(2) = 2(2!)² + 19(2)³ + 4(2)²f(2) = 2(2 × 1)² + 19(2 × 2 × 2) + 4(2 × 2)f(2) = 2(2)² + 19(4 × 2) + 4(4)f(2) = 2(2 × 2) + 19(8) + 16f(2) = 2(4) + 152 + 16f(2) = 8 + 152 + 16f(2) = 160 + 16f(2) = 176f(3) = 3(3!)² + 19(3)³ + 4(3)²f(3) = 3(3 × 2 × 1)² + 19(3 × 3 × 3) + 4(3 × 3)f(3) = 3(6 × 1) + 19(9 × 3) + 4(9)f(3) = 3(6)² + 19(27) + 36f(3) = 3(6 × 6) + 513 + 36f(3) = 3(36) + 513 + 36f(3) = 108 + 513 + 36f(3) = 621 + 36f(3) = 657Jawaban:✍ PenyelesaianJika:f(x) = x(x!)² + 19x³ + 4x² Maka:f(2) = 2(2!)² + 19(2)³ + 4(2)²f(2) = 2(2 × 1)² + 19(2 × 2 × 2) + 4(2 × 2)f(2) = 2(2)² + 19(4 × 2) + 4(4)f(2) = 2(2 × 2) + 19(8) + 16f(2) = 2(4) + 152 + 16f(2) = 8 + 152 + 16f(2) = 160 + 16f(2) = 176f(3) = 3(3!)² + 19(3)³ + 4(3)²f(3) = 3(3 × 2 × 1)² + 19(3 × 3 × 3) + 4(3 × 3)f(3) = 3(6 × 1) + 19(9 × 3) + 4(9)f(3) = 3(6)² + 19(27) + 36f(3) = 3(6 × 6) + 513 + 36f(3) = 3(36) + 513 + 36f(3) = 108 + 513 + 36f(3) = 621 + 36f(3) = 657Jawaban:✍ PenyelesaianJika:f(x) = x(x!)² + 19x³ + 4x² Maka:f(2) = 2(2!)² + 19(2)³ + 4(2)²f(2) = 2(2 × 1)² + 19(2 × 2 × 2) + 4(2 × 2)f(2) = 2(2)² + 19(4 × 2) + 4(4)f(2) = 2(2 × 2) + 19(8) + 16f(2) = 2(4) + 152 + 16f(2) = 8 + 152 + 16f(2) = 160 + 16f(2) = 176f(3) = 3(3!)² + 19(3)³ + 4(3)²f(3) = 3(3 × 2 × 1)² + 19(3 × 3 × 3) + 4(3 × 3)f(3) = 3(6 × 1) + 19(9 × 3) + 4(9)f(3) = 3(6)² + 19(27) + 36f(3) = 3(6 × 6) + 513 + 36f(3) = 3(36) + 513 + 36f(3) = 108 + 513 + 36f(3) = 621 + 36f(3) = 657Jawaban:✍ PenyelesaianJika:f(x) = x(x!)² + 19x³ + 4x² Maka:f(2) = 2(2!)² + 19(2)³ + 4(2)²f(2) = 2(2 × 1)² + 19(2 × 2 × 2) + 4(2 × 2)f(2) = 2(2)² + 19(4 × 2) + 4(4)f(2) = 2(2 × 2) + 19(8) + 16f(2) = 2(4) + 152 + 16f(2) = 8 + 152 + 16f(2) = 160 + 16f(2) = 176f(3) = 3(3!)² + 19(3)³ + 4(3)²f(3) = 3(3 × 2 × 1)² + 19(3 × 3 × 3) + 4(3 × 3)f(3) = 3(6 × 1) + 19(9 × 3) + 4(9)f(3) = 3(6)² + 19(27) + 36f(3) = 3(6 × 6) + 513 + 36f(3) = 3(36) + 513 + 36f(3) = 108 + 513 + 36f(3) = 621 + 36f(3) = 657Jawaban:✍ PenyelesaianJika:f(x) = x(x!)² + 19x³ + 4x² Maka:f(2) = 2(2!)² + 19(2)³ + 4(2)²f(2) = 2(2 × 1)² + 19(2 × 2 × 2) + 4(2 × 2)f(2) = 2(2)² + 19(4 × 2) + 4(4)f(2) = 2(2 × 2) + 19(8) + 16f(2) = 2(4) + 152 + 16f(2) = 8 + 152 + 16f(2) = 160 + 16f(2) = 176f(3) = 3(3!)² + 19(3)³ + 4(3)²f(3) = 3(3 × 2 × 1)² + 19(3 × 3 × 3) + 4(3 × 3)f(3) = 3(6 × 1) + 19(9 × 3) + 4(9)f(3) = 3(6)² + 19(27) + 36f(3) = 3(6 × 6) + 513 + 36f(3) = 3(36) + 513 + 36f(3) = 108 + 513 + 36f(3) = 621 + 36f(3) = 657

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Last Update: Mon, 03 Oct 22