1. Sekolah Dasar
  2. Sekolah Menengah Pertama
  3. Sekolah Menengah Atas
  4. Mata Pelajaran
  5. Programming

Q.ome back[tex] \\ [/tex]f(p) = 10p + 6(p + p)f(1)

Berikut ini adalah pertanyaan dari myntr1 pada mata pelajaran Matematika untuk jenjang Sekolah Menengah Pertama

Q.ome back \\
f(p) = 10p + 6(p + p)
f(1) = ..
f(3) = ..
f(6) = ..
f(8) = ...
​ \\
\tt\color{hotpink}{{{RULES : }}}
≈ Pakai cara!
≈ ngasal⬄report!
≈ Rapi!
≈ Salah⬄koreksi 30 menit!
------------------------------------
​ \\
_.​

Jawaban dan Penjelasan

Berikut ini adalah pilihan jawaban terbaik dari pertanyaan diatas.

f(p) = 10p + 6(p + p), maka:

f(1) = 22

f(3) = 66

f(6) = 132

f(8) = 176

Pendahuluan

Definisi dari fungsi atau pemetaan yakni adalah suatu relasi khusus yang menentukan setiap himpunan A ke himpunan B dengan tepat satu anggota.

Rumus fungsi:

f(x) = ax + b

Contoh:

f(x) = 2x + 3, nilai fungsi untuk x = 2

f(2) = 2(2) + 3

f(2) = 4 + 3

f(2) = 7

Pembahasan

Diketahui:

  • f(p) = 10p + 6(p + p)

Ditanya:

  • f(1) = ..
  • f(3) = ..
  • f(6) = ..
  • f(8) = ...

Jawab:

  • p = 1

f(p) = 10p + 6(p + p)

f(1) = 10(1) + 6(1 + 1)

f(1) = 10 + 6(2)

f(1) = 10 + 12

f(1) = 22

  • p = 3

f(p) = 10p + 6(p + p)

f(3) = 10(3) + 6(3 + 3)

f(3) = 30 + 6(6)

f(3) = 30 + 36

f(3) = 66

  • p = 6

f(p) = 10p + 6(p + p)

f(6) = 10(6) + 6(6 + 6)

f(6) = 60 + 6(12)

f(6) = 60 + 72

f(6) = 132

  • p = 8

f(p) = 10p + 6(p + p)

f(8) = 10(8) + 6(8 + 8)

f(8) = 80 + 6(16)

f(8) = 80 + 96

f(8) = 176

Pelajari lebih lanjut:

  1. Pengertian relasi dan fungsi: yomemimo.com/tugas/1040698
  2. Materi tentang rumus fungsi: yomemimo.com/tugas/18134817
  3. Materi tentang mentukan nilai fungsi: yomemimo.com/tugas/20312811

____________________

Detail Jawaban:

Kelas : 8 SMP

Mapel : Matematika

Materi : Relasi dan Fungsi

Kode : 8.2.2

#SolusiBrainlyCommunity

Diketahuif(p) = 10p + 6(p + p) [tex]\\[/tex]Ditanyaf(1) =f(3) =f(6) =f(8) =[tex]\\[/tex]Jawab :[tex]\boxed{ F(1) }[/tex]f(p) = 10p + 6(p + p) f(1) = 10(1) + 6(1 + 1) f(1) = 10(1) + 6(2) f(1) = ( 10 × 1 ) + 6(2) f(1) = 10 + ( 6 + 6 ) f(1) = 10 + 12f(1) = [tex]\bold{ 22 }[/tex][tex]\\[/tex][tex]\boxed{ F(3) }[/tex]f(p) = 10p + 6(p + p) f(3) = 10(3) + 6(3 + 3) f(3) = 10(3) + 6(6) f(3) = ( 10 + 10 + 10 ) + 6(6) f(3) = ( 20 + 10 ) + 6(6) f(3) = 30 + 6(6) f(3) = 30 + ( 6 + 6 + 6 + 6 + 6 + 6 ) f(3) = 30 + ( 12 + 6 + 6 + 6 + 6 ) f(3) = 30 + ( 12 + 12 + 6 + 6 ) f(3) = 30 + ( 12 + 12 + 12 ) f(3) = 30 + ( 24 + 12 ) f(3) = 30 + 36f(3) = [tex]\bold{ 66 }[/tex][tex]\\[/tex][tex]\boxed{ F(6) }[/tex]f(p) = 10p + 6(p + p) f(6) = 10(6) + 6(6 + 6) f(6) = 10(6) + 6(12) f(6) = ( 10 × 6 ) + 6(12) f(6) = 60 + 6(12) f(6) = 60 + ( 6 × 12 ) f(6) = 60 + 72f(6) = [tex]\bold{ 132 }[/tex][tex]\\[/tex][tex]\boxed{ F(8) }[/tex]f(p) = 10p + 6(p + p) f(8) = 10(8) + 6(8 + 8)f(8) = 10(8) + 6(16)f(8) = ( 10 × 8 ) + 6(16) f(8) = 80 + 6(16) f(8) = 80 + ( 6 × 16 ) f(8) = 80 + 96f(8) = [tex]\bold{ 176 }[/tex][tex]\\[/tex]Kesimpulan[tex]\bold{ f(p) = 10p + 6(p + p) }[/tex][tex]\bold{ f(1) = 22 }[/tex][tex]\bold{ f(3) = 66 }[/tex][tex]\bold{ f(6) = 132 }[/tex][tex]\bold{ f(8) = 176 }[/tex]Diketahuif(p) = 10p + 6(p + p) [tex]\\[/tex]Ditanyaf(1) =f(3) =f(6) =f(8) =[tex]\\[/tex]Jawab :[tex]\boxed{ F(1) }[/tex]f(p) = 10p + 6(p + p) f(1) = 10(1) + 6(1 + 1) f(1) = 10(1) + 6(2) f(1) = ( 10 × 1 ) + 6(2) f(1) = 10 + ( 6 + 6 ) f(1) = 10 + 12f(1) = [tex]\bold{ 22 }[/tex][tex]\\[/tex][tex]\boxed{ F(3) }[/tex]f(p) = 10p + 6(p + p) f(3) = 10(3) + 6(3 + 3) f(3) = 10(3) + 6(6) f(3) = ( 10 + 10 + 10 ) + 6(6) f(3) = ( 20 + 10 ) + 6(6) f(3) = 30 + 6(6) f(3) = 30 + ( 6 + 6 + 6 + 6 + 6 + 6 ) f(3) = 30 + ( 12 + 6 + 6 + 6 + 6 ) f(3) = 30 + ( 12 + 12 + 6 + 6 ) f(3) = 30 + ( 12 + 12 + 12 ) f(3) = 30 + ( 24 + 12 ) f(3) = 30 + 36f(3) = [tex]\bold{ 66 }[/tex][tex]\\[/tex][tex]\boxed{ F(6) }[/tex]f(p) = 10p + 6(p + p) f(6) = 10(6) + 6(6 + 6) f(6) = 10(6) + 6(12) f(6) = ( 10 × 6 ) + 6(12) f(6) = 60 + 6(12) f(6) = 60 + ( 6 × 12 ) f(6) = 60 + 72f(6) = [tex]\bold{ 132 }[/tex][tex]\\[/tex][tex]\boxed{ F(8) }[/tex]f(p) = 10p + 6(p + p) f(8) = 10(8) + 6(8 + 8)f(8) = 10(8) + 6(16)f(8) = ( 10 × 8 ) + 6(16) f(8) = 80 + 6(16) f(8) = 80 + ( 6 × 16 ) f(8) = 80 + 96f(8) = [tex]\bold{ 176 }[/tex][tex]\\[/tex]Kesimpulan[tex]\bold{ f(p) = 10p + 6(p + p) }[/tex][tex]\bold{ f(1) = 22 }[/tex][tex]\bold{ f(3) = 66 }[/tex][tex]\bold{ f(6) = 132 }[/tex][tex]\bold{ f(8) = 176 }[/tex]Diketahuif(p) = 10p + 6(p + p) [tex]\\[/tex]Ditanyaf(1) =f(3) =f(6) =f(8) =[tex]\\[/tex]Jawab :[tex]\boxed{ F(1) }[/tex]f(p) = 10p + 6(p + p) f(1) = 10(1) + 6(1 + 1) f(1) = 10(1) + 6(2) f(1) = ( 10 × 1 ) + 6(2) f(1) = 10 + ( 6 + 6 ) f(1) = 10 + 12f(1) = [tex]\bold{ 22 }[/tex][tex]\\[/tex][tex]\boxed{ F(3) }[/tex]f(p) = 10p + 6(p + p) f(3) = 10(3) + 6(3 + 3) f(3) = 10(3) + 6(6) f(3) = ( 10 + 10 + 10 ) + 6(6) f(3) = ( 20 + 10 ) + 6(6) f(3) = 30 + 6(6) f(3) = 30 + ( 6 + 6 + 6 + 6 + 6 + 6 ) f(3) = 30 + ( 12 + 6 + 6 + 6 + 6 ) f(3) = 30 + ( 12 + 12 + 6 + 6 ) f(3) = 30 + ( 12 + 12 + 12 ) f(3) = 30 + ( 24 + 12 ) f(3) = 30 + 36f(3) = [tex]\bold{ 66 }[/tex][tex]\\[/tex][tex]\boxed{ F(6) }[/tex]f(p) = 10p + 6(p + p) f(6) = 10(6) + 6(6 + 6) f(6) = 10(6) + 6(12) f(6) = ( 10 × 6 ) + 6(12) f(6) = 60 + 6(12) f(6) = 60 + ( 6 × 12 ) f(6) = 60 + 72f(6) = [tex]\bold{ 132 }[/tex][tex]\\[/tex][tex]\boxed{ F(8) }[/tex]f(p) = 10p + 6(p + p) f(8) = 10(8) + 6(8 + 8)f(8) = 10(8) + 6(16)f(8) = ( 10 × 8 ) + 6(16) f(8) = 80 + 6(16) f(8) = 80 + ( 6 × 16 ) f(8) = 80 + 96f(8) = [tex]\bold{ 176 }[/tex][tex]\\[/tex]Kesimpulan[tex]\bold{ f(p) = 10p + 6(p + p) }[/tex][tex]\bold{ f(1) = 22 }[/tex][tex]\bold{ f(3) = 66 }[/tex][tex]\bold{ f(6) = 132 }[/tex][tex]\bold{ f(8) = 176 }[/tex]Diketahuif(p) = 10p + 6(p + p) [tex]\\[/tex]Ditanyaf(1) =f(3) =f(6) =f(8) =[tex]\\[/tex]Jawab :[tex]\boxed{ F(1) }[/tex]f(p) = 10p + 6(p + p) f(1) = 10(1) + 6(1 + 1) f(1) = 10(1) + 6(2) f(1) = ( 10 × 1 ) + 6(2) f(1) = 10 + ( 6 + 6 ) f(1) = 10 + 12f(1) = [tex]\bold{ 22 }[/tex][tex]\\[/tex][tex]\boxed{ F(3) }[/tex]f(p) = 10p + 6(p + p) f(3) = 10(3) + 6(3 + 3) f(3) = 10(3) + 6(6) f(3) = ( 10 + 10 + 10 ) + 6(6) f(3) = ( 20 + 10 ) + 6(6) f(3) = 30 + 6(6) f(3) = 30 + ( 6 + 6 + 6 + 6 + 6 + 6 ) f(3) = 30 + ( 12 + 6 + 6 + 6 + 6 ) f(3) = 30 + ( 12 + 12 + 6 + 6 ) f(3) = 30 + ( 12 + 12 + 12 ) f(3) = 30 + ( 24 + 12 ) f(3) = 30 + 36f(3) = [tex]\bold{ 66 }[/tex][tex]\\[/tex][tex]\boxed{ F(6) }[/tex]f(p) = 10p + 6(p + p) f(6) = 10(6) + 6(6 + 6) f(6) = 10(6) + 6(12) f(6) = ( 10 × 6 ) + 6(12) f(6) = 60 + 6(12) f(6) = 60 + ( 6 × 12 ) f(6) = 60 + 72f(6) = [tex]\bold{ 132 }[/tex][tex]\\[/tex][tex]\boxed{ F(8) }[/tex]f(p) = 10p + 6(p + p) f(8) = 10(8) + 6(8 + 8)f(8) = 10(8) + 6(16)f(8) = ( 10 × 8 ) + 6(16) f(8) = 80 + 6(16) f(8) = 80 + ( 6 × 16 ) f(8) = 80 + 96f(8) = [tex]\bold{ 176 }[/tex][tex]\\[/tex]Kesimpulan[tex]\bold{ f(p) = 10p + 6(p + p) }[/tex][tex]\bold{ f(1) = 22 }[/tex][tex]\bold{ f(3) = 66 }[/tex][tex]\bold{ f(6) = 132 }[/tex][tex]\bold{ f(8) = 176 }[/tex]Diketahuif(p) = 10p + 6(p + p) [tex]\\[/tex]Ditanyaf(1) =f(3) =f(6) =f(8) =[tex]\\[/tex]Jawab :[tex]\boxed{ F(1) }[/tex]f(p) = 10p + 6(p + p) f(1) = 10(1) + 6(1 + 1) f(1) = 10(1) + 6(2) f(1) = ( 10 × 1 ) + 6(2) f(1) = 10 + ( 6 + 6 ) f(1) = 10 + 12f(1) = [tex]\bold{ 22 }[/tex][tex]\\[/tex][tex]\boxed{ F(3) }[/tex]f(p) = 10p + 6(p + p) f(3) = 10(3) + 6(3 + 3) f(3) = 10(3) + 6(6) f(3) = ( 10 + 10 + 10 ) + 6(6) f(3) = ( 20 + 10 ) + 6(6) f(3) = 30 + 6(6) f(3) = 30 + ( 6 + 6 + 6 + 6 + 6 + 6 ) f(3) = 30 + ( 12 + 6 + 6 + 6 + 6 ) f(3) = 30 + ( 12 + 12 + 6 + 6 ) f(3) = 30 + ( 12 + 12 + 12 ) f(3) = 30 + ( 24 + 12 ) f(3) = 30 + 36f(3) = [tex]\bold{ 66 }[/tex][tex]\\[/tex][tex]\boxed{ F(6) }[/tex]f(p) = 10p + 6(p + p) f(6) = 10(6) + 6(6 + 6) f(6) = 10(6) + 6(12) f(6) = ( 10 × 6 ) + 6(12) f(6) = 60 + 6(12) f(6) = 60 + ( 6 × 12 ) f(6) = 60 + 72f(6) = [tex]\bold{ 132 }[/tex][tex]\\[/tex][tex]\boxed{ F(8) }[/tex]f(p) = 10p + 6(p + p) f(8) = 10(8) + 6(8 + 8)f(8) = 10(8) + 6(16)f(8) = ( 10 × 8 ) + 6(16) f(8) = 80 + 6(16) f(8) = 80 + ( 6 × 16 ) f(8) = 80 + 96f(8) = [tex]\bold{ 176 }[/tex][tex]\\[/tex]Kesimpulan[tex]\bold{ f(p) = 10p + 6(p + p) }[/tex][tex]\bold{ f(1) = 22 }[/tex][tex]\bold{ f(3) = 66 }[/tex][tex]\bold{ f(6) = 132 }[/tex][tex]\bold{ f(8) = 176 }[/tex]

Semoga dengan pertanyaan yang sudah terjawab oleh LaureliaNazua dapat membantu memudahkan mengerjakan soal, tugas dan PR sekolah kalian.

Apabila terdapat kesalahan dalam mengerjakan soal, silahkan koreksi jawaban dengan mengirimkan email ke yomemimo.com melalui halaman Contact

Last Update: Wed, 21 Sep 22
<< Previous Post
Next Post >>