a) Tabung dgn d= 24cm, r= 12dm dan t= 40dm, π= 3,14

* Luas permukaan tabung= 2πr (r+t)

= 2 x 3,14 x 12 (12+40)

= 75,36 (52)

= 3.918,72dm²

* Volume Tabung= πr²t

= 3,14 x 12 x 12 x 40

= 18.086,4dm³

••••••••••

b) Kerucut dgn r= 8dm, t= 15dm, π= 3,14

Garis pelukis/s

s²= √r²+t²

s²= √8²+15²

s²= √64+225

s²= √289

s= √289, s= 17dm

*Luas permukaan kerucut= πr (r+s)

= 3,14 x 8 (8+17)

= 25,12 (25)

= 628dm²

*Volume Kerucut= 1/3πr²t

= 1/3 x 3,14 x 8 x 8 x 15

= 1.004,8dm³

•••••••

c) Bola dgn r= 24cm, π= 3,14

* Luas permukaan bola= 4πr²

= 4 x 3,14 x 24 x 24

= 7.234,56cm²

*Volume Bola= 4/3 x π x r³

= 4/3 x 3,14 x 24 x 24 x 24

= 14.469,12cm³