Materi : Bangun Ruang dan Volume

Soal Nomor 1

Volume Tabung

V = π × r² × t

V = 22/7 × 7 × 7 × 30

V = 22 × 1 × 7 × 30

V = 660 × 7

V = { 4.620 satuan³ }

Soal Nomor 2

Luas Permukaan Tabung

Lp = 2 × π × r² + π × d × t

Lp = 2 × 22/7 × 7 × 7 + 22/7 × 14 × 30

Lp = 44 × 7 + 22 × 2 × 30

Lp = 308 satuan² + 1.320 satuan²

Lp = { 1.628 satuan² }

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Tinggi Kerucut

t² = s² - a²

t² = 25² - 7²

t² = 625 - 49

t² = 576

t = √576

[ t = 24 cm ]

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Soal Nomor 3

Volume Kerucut

V = ⅓ × π × r² × t

V = ⅓ × 22/7 × 7 × 7 × 18

V = 22 × 7 × 6

V = 132 × 7

V = ( 700 + 210 + 14 ) satuan²

V = { 924 satuan³ }

Soal Nomor 4

Luas Permukaan Kerucut

Lp = π × r × ( r + s )

Lp = 22/7 × 7 × ( 7 + 25 )

Lp = 22 × 32

Lp = { 704 satuan² }

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