Berikut ini adalah pertanyaan dari fitri129062 pada mata pelajaran Matematika untuk jenjang Sekolah Menengah Pertama
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Jawaban dan Penjelasan
Berikut ini adalah pilihan jawaban terbaik dari pertanyaan diatas.
Penjelasan dengan langkah-langkah:
1.
(-2, 6) (4,1)
Persamaan =
Gradien
2.
m= -2
P = (3, -2)
3.a
m = 3
D = (0, 5)
3.b
m = -2
A = (2, 4)
3.c
m = 4
B = ( -3, -4)
3d,
B = ( -3, -4) dan C = (4 , -6)
![Penjelasan dengan langkah-langkah:1.(-2, 6) (4,1)Persamaan =[tex] \frac{y - y_{1}}{y_{2} - y_{1 }} = \frac{x - x_{1}}{x_{2} - x_{1 }} \\ \\ \frac{y - 6}{1 - 6} = \frac{x - ( - 2)}{4 - ( - 2)} \\ \\ \frac{y - 6}{ - 5} = \frac{x + 2}{6} \\ \\ 6(y - 6) = - 5(x + 2) \\ 6y - 36 = - 5x - 10 \\ 6y = - 5x - 10 + 36 \\ 6y = - 5x + 26[/tex]Gradien [tex]6y = - 5x + 26 \\ \\ m = - \frac{5}{6} = - 0.83[/tex]2.m= -2P = (3, -2)[tex]y - y_{1} = m(x - x_{1}) \\ y - ( - 2) = - 2(x - 3) \\ y + 2 = - 2x + 6 \\ y = - 2x + 6 - 2 \\ y = - 2x + 4[/tex]3.am = 3D = (0, 5)[tex]y - y_{1} = m(x - x_{1}) \\ y - 5 =3(x - 0) \\ y - 5 = 3x \\ y = 3x + 5[/tex]3.b m = -2A = (2, 4)[tex]y - y_{1} = m(x - x_{1}) \\ y - 4 = - 2(x - 2) \\ y - 4 = - 2x + 4 \\ y = - 2x + 4 + 4 \\ y = - 2x + 8[/tex]3.cm = 4B = ( -3, -4)[tex]y - y_{1} = m(x - x_{1}) \\ y - ( - 4) = 4(x - ( - 3) \\ y + 4 = 4(x + 3) \\ y + 4 = 4x + 12 \\ y = 4x + 12 - 4 \\ y = 4x + 8[/tex]3d,B = ( -3, -4) dan C = (4 , -6)[tex] \frac{y - y_{1}}{y_{2} - y_{1 }} = \frac{x - x_{1}}{x_{2} - x_{1}} \\ \\ \frac{y - ( - 4)}{ - 6 - ( - 4)} = \frac{x - ( - 3)}{4 - ( - 3)} \\ \\ \frac{y + 4}{ - 2} = \frac{x + 3}{7} \\ \\ 7(y + 4) = - 2(x + 3) \\ 7y + 28 = - 2x - 6 \\ 7y = - 2x - 6 - 28 \\ 7y = - 2x - 34[/tex]](https://id-static.z-dn.net/files/d28/9c52fc2a956b487030c5d3d21e484fbe.jpg)
![Penjelasan dengan langkah-langkah:1.(-2, 6) (4,1)Persamaan =[tex] \frac{y - y_{1}}{y_{2} - y_{1 }} = \frac{x - x_{1}}{x_{2} - x_{1 }} \\ \\ \frac{y - 6}{1 - 6} = \frac{x - ( - 2)}{4 - ( - 2)} \\ \\ \frac{y - 6}{ - 5} = \frac{x + 2}{6} \\ \\ 6(y - 6) = - 5(x + 2) \\ 6y - 36 = - 5x - 10 \\ 6y = - 5x - 10 + 36 \\ 6y = - 5x + 26[/tex]Gradien [tex]6y = - 5x + 26 \\ \\ m = - \frac{5}{6} = - 0.83[/tex]2.m= -2P = (3, -2)[tex]y - y_{1} = m(x - x_{1}) \\ y - ( - 2) = - 2(x - 3) \\ y + 2 = - 2x + 6 \\ y = - 2x + 6 - 2 \\ y = - 2x + 4[/tex]3.am = 3D = (0, 5)[tex]y - y_{1} = m(x - x_{1}) \\ y - 5 =3(x - 0) \\ y - 5 = 3x \\ y = 3x + 5[/tex]3.b m = -2A = (2, 4)[tex]y - y_{1} = m(x - x_{1}) \\ y - 4 = - 2(x - 2) \\ y - 4 = - 2x + 4 \\ y = - 2x + 4 + 4 \\ y = - 2x + 8[/tex]3.cm = 4B = ( -3, -4)[tex]y - y_{1} = m(x - x_{1}) \\ y - ( - 4) = 4(x - ( - 3) \\ y + 4 = 4(x + 3) \\ y + 4 = 4x + 12 \\ y = 4x + 12 - 4 \\ y = 4x + 8[/tex]3d,B = ( -3, -4) dan C = (4 , -6)[tex] \frac{y - y_{1}}{y_{2} - y_{1 }} = \frac{x - x_{1}}{x_{2} - x_{1}} \\ \\ \frac{y - ( - 4)}{ - 6 - ( - 4)} = \frac{x - ( - 3)}{4 - ( - 3)} \\ \\ \frac{y + 4}{ - 2} = \frac{x + 3}{7} \\ \\ 7(y + 4) = - 2(x + 3) \\ 7y + 28 = - 2x - 6 \\ 7y = - 2x - 6 - 28 \\ 7y = - 2x - 34[/tex]](https://id-static.z-dn.net/files/df1/202f8b220559214235612869df878433.jpg)
![Penjelasan dengan langkah-langkah:1.(-2, 6) (4,1)Persamaan =[tex] \frac{y - y_{1}}{y_{2} - y_{1 }} = \frac{x - x_{1}}{x_{2} - x_{1 }} \\ \\ \frac{y - 6}{1 - 6} = \frac{x - ( - 2)}{4 - ( - 2)} \\ \\ \frac{y - 6}{ - 5} = \frac{x + 2}{6} \\ \\ 6(y - 6) = - 5(x + 2) \\ 6y - 36 = - 5x - 10 \\ 6y = - 5x - 10 + 36 \\ 6y = - 5x + 26[/tex]Gradien [tex]6y = - 5x + 26 \\ \\ m = - \frac{5}{6} = - 0.83[/tex]2.m= -2P = (3, -2)[tex]y - y_{1} = m(x - x_{1}) \\ y - ( - 2) = - 2(x - 3) \\ y + 2 = - 2x + 6 \\ y = - 2x + 6 - 2 \\ y = - 2x + 4[/tex]3.am = 3D = (0, 5)[tex]y - y_{1} = m(x - x_{1}) \\ y - 5 =3(x - 0) \\ y - 5 = 3x \\ y = 3x + 5[/tex]3.b m = -2A = (2, 4)[tex]y - y_{1} = m(x - x_{1}) \\ y - 4 = - 2(x - 2) \\ y - 4 = - 2x + 4 \\ y = - 2x + 4 + 4 \\ y = - 2x + 8[/tex]3.cm = 4B = ( -3, -4)[tex]y - y_{1} = m(x - x_{1}) \\ y - ( - 4) = 4(x - ( - 3) \\ y + 4 = 4(x + 3) \\ y + 4 = 4x + 12 \\ y = 4x + 12 - 4 \\ y = 4x + 8[/tex]3d,B = ( -3, -4) dan C = (4 , -6)[tex] \frac{y - y_{1}}{y_{2} - y_{1 }} = \frac{x - x_{1}}{x_{2} - x_{1}} \\ \\ \frac{y - ( - 4)}{ - 6 - ( - 4)} = \frac{x - ( - 3)}{4 - ( - 3)} \\ \\ \frac{y + 4}{ - 2} = \frac{x + 3}{7} \\ \\ 7(y + 4) = - 2(x + 3) \\ 7y + 28 = - 2x - 6 \\ 7y = - 2x - 6 - 28 \\ 7y = - 2x - 34[/tex]](https://id-static.z-dn.net/files/d89/2708953eae3279740f249a597632306f.jpg)
![Penjelasan dengan langkah-langkah:1.(-2, 6) (4,1)Persamaan =[tex] \frac{y - y_{1}}{y_{2} - y_{1 }} = \frac{x - x_{1}}{x_{2} - x_{1 }} \\ \\ \frac{y - 6}{1 - 6} = \frac{x - ( - 2)}{4 - ( - 2)} \\ \\ \frac{y - 6}{ - 5} = \frac{x + 2}{6} \\ \\ 6(y - 6) = - 5(x + 2) \\ 6y - 36 = - 5x - 10 \\ 6y = - 5x - 10 + 36 \\ 6y = - 5x + 26[/tex]Gradien [tex]6y = - 5x + 26 \\ \\ m = - \frac{5}{6} = - 0.83[/tex]2.m= -2P = (3, -2)[tex]y - y_{1} = m(x - x_{1}) \\ y - ( - 2) = - 2(x - 3) \\ y + 2 = - 2x + 6 \\ y = - 2x + 6 - 2 \\ y = - 2x + 4[/tex]3.am = 3D = (0, 5)[tex]y - y_{1} = m(x - x_{1}) \\ y - 5 =3(x - 0) \\ y - 5 = 3x \\ y = 3x + 5[/tex]3.b m = -2A = (2, 4)[tex]y - y_{1} = m(x - x_{1}) \\ y - 4 = - 2(x - 2) \\ y - 4 = - 2x + 4 \\ y = - 2x + 4 + 4 \\ y = - 2x + 8[/tex]3.cm = 4B = ( -3, -4)[tex]y - y_{1} = m(x - x_{1}) \\ y - ( - 4) = 4(x - ( - 3) \\ y + 4 = 4(x + 3) \\ y + 4 = 4x + 12 \\ y = 4x + 12 - 4 \\ y = 4x + 8[/tex]3d,B = ( -3, -4) dan C = (4 , -6)[tex] \frac{y - y_{1}}{y_{2} - y_{1 }} = \frac{x - x_{1}}{x_{2} - x_{1}} \\ \\ \frac{y - ( - 4)}{ - 6 - ( - 4)} = \frac{x - ( - 3)}{4 - ( - 3)} \\ \\ \frac{y + 4}{ - 2} = \frac{x + 3}{7} \\ \\ 7(y + 4) = - 2(x + 3) \\ 7y + 28 = - 2x - 6 \\ 7y = - 2x - 6 - 28 \\ 7y = - 2x - 34[/tex]](https://id-static.z-dn.net/files/d85/02389e26e7bed5e51785146f8495ba59.jpg)
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Last Update: Tue, 25 Jan 22