Jawab:

1. domain = {-3,-2,-1,0,1}

  kodomain = {1,2,4,9}

  range = {2,4,9}

2. f(x) = 3x - 6

   f(5) = 3(5) - 6 = 15 -6 = 9

   f(10) = 3(10) -6 = 30-6=14

   f(-5) = 3(-5) - 6 = -15 -6 = -21

3. f(x) = -2x + 12

   domain = -4 < x < 3 {x=-4,-3,-2,-1,0,1,2,3}

   f(-4)= -2(-4) + 12 = 20

   f(-3) = -2(-3) + 12 = 18

   f(-2) = -2(-2) + 12 = 16

   f(-1) = -2(-1) + 12 = 14

   f(0) = -2(0) + 12 = 12

  f(1) = -2(1) + 12 = 10

   f(2) = -2(2) + 12 = 8

    f(3) = -2(3) + 12 =6

GRAFIK FUNGSI ADA PADA GAMBAR DIBAWAH !

4. F(X) = x² + 3X - 8

 domain = { -3 < x < 3} maka x=-3,-2,-1,0,1,2,3

  f(-3) = 9 - 9 -8 = -8

  f(-2) = 4 -6 -8 = -10

  f(-1) = 1 -3 -8 = -10

  f(0) = 0 + 0 -8 = -8

  f(1) = 1 +3 -8 = -4

   f(2) = 4 + 6 -8 = 2

  f(3) = 9 + 9 -8 = 10

grafik ada pada gambar dibawah

5. f(x) = 5x

   F(x+3) = f(x) + 3 = 5x + 3

   f(-3 -x) = -3 -f(x) = -3 -5x

    f(2x-5) = 2f(x) -5 =10x -5